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AleksandrR [38]
3 years ago
11

NEED HELP FAST Identify whether this molecule is a monomer or polymer and explain your answer.

Chemistry
2 answers:
Licemer1 [7]3 years ago
6 0

Its a polymer because there are two of the same monomer (and the CH2OH which is different) that join together to create the one polymer. By definition a polymer is a molecule made up of smaller repeating monomers.

IrinaK [193]3 years ago
4 0
ITS A POLYMER OODBZBS
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In part 3 of the lab, you discovered the relationship between temperature (T) and volume (V) of a gas.
rewona [7]

\frac{V1}{T1} = k

<u>Explanation:</u>

The relation between volume, V of gas and Temperature, T of a gas is related by Charles Law.

This law states that the volume of a given amount of gas held at a constant pressure is directly proportional to the Kelvin temperature

Thus,

\frac{V}{T} = k

where k is a constant

Therefore,

\frac{V1}{T1} = \frac{V2}{T2\\} = \frac{V3}{T3} ...

This shows, as the volume of a gas goes up, the temperature also goes up and vice-versa.

7 0
3 years ago
In the following reaction, how many liters of o2 will produce 43.62 liters of co2 at stp? c3h8 5 o2 3 co2 4 h2o
antoniya [11.8K]
The balanced chemical reaction:

C3H8 + 5O2 = 3CO2 + 4H2O

We are given the amount of the carbon dioxide to be produced. This will be the starting point of our calculations.

<span>43.62 L CO2 ( 1 mol CO2 / 22.4 L CO2 ) (5 mol O2 / 3 mol CO2 ) ( 22.4 L O2 / 1 mol O2) = 72.7 L O2</span>



4 0
4 years ago
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4.8 tons of pig ovaries were required to extract 12.0 mg of estrogen
bearhunter [10]
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3 years ago
A student constructs a galvanic cell that has a strip of iron metal immersed in a solution of 0.1M Fe(NO3)2 as one half-cell and
MrMuchimi

Answer:

Fe

Explanation:

The cell potential is:

ΔE°cell = E°red(red) - E°red(oxid)

Where, E°red(red) is the reduction potential of the substance that is reducing, and E°red(oxid) is the reduction potential of the substance that is oxidizing. For the reaction be spontaneous and happen, ΔE°cell > 0.

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4 0
3 years ago
Identify the intermediate leads to the major product for the reaction of 2-methyl-2-butene with hydrogen bromide in the presence
pishuonlain [190]

Answer:

II

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The intermediate in anti Markovnikov  addition involves the most stable radical, in this case, it is a tertiary radical as shown in the images attached. The most stable radical is II hence it leads to the major product shown in the other image.

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3 years ago
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