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SpyIntel [72]
3 years ago
13

Calculate the cost of running an electric laundry iron for 8 hours, if the cost of 1 unit of energy is N24.00 and the rating of

the iron is 1200w,240v​
Physics
1 answer:
bezimeni [28]3 years ago
5 0

Answer:

Cost of energy = N230.4

Explanation:

Given the following data;

Time = 8 hours

Power = 1200 W

Voltage = 240 V

Cost of energy = N24

To find the cost of running an electric laundry iron;

First of all, we would determine the energy consumption of the iron.

Energy = power * time

Energy = 1200 * 8

Energy = 9600 Watt-hour = 9.6 Kwh (1 Kilowatts is equal to 1000 watts).

Next, we find the cost of energy;

Cost of energy = 9.6 * 24

Cost of energy = N230.4

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"a grindstone of radius 4.0 m is initially spinning with an angular speed of 8.0 rad/s. the angular speed is then increased to 1
kotegsom [21]

The average angular speed of the grindstone is 10 rad/s

\texttt{ }

<h3>Further explanation</h3>

<em>Let's recall </em><em>Angular Speed</em><em> formula as follows:</em>

\boxed{ \omega = \omega_o + \alpha t }

\boxed{ \theta = \omega_o t + \frac{1}{2} \alpha t^2 }

\boxed{ \omega^2 = \omega_o^2 + 2 \alpha \theta }

\boxed{ \theta = \frac{( \omega + \omega_o )}{2} t }

<em>where :</em>

<em>ω = final angular speed ( rad/s )</em>

<em>ω₀ = initial angular speed ( rad/s )</em>

<em>α = angular acceleration ( rad/s² )</em>

<em>t = elapsed time ( s )</em>

<em>θ = angular displacement ( rad )</em>

\texttt{ }

<u>Given:</u>

radius of the grindstone = R = 4.0 m

initial angular speed = ω₀ = 8.0 rad/s

final angular speed = ω = 12 rad/s

elapsed time = t = 4.0 seconds

<u>Asked:</u>

average angular speed = ?

<u>Solution:</u>

<em>Firstly , we will calculate </em><em>angular displacement </em><em>as follows:</em>

\theta = \frac{( \omega + \omega_o )}{2} t

\theta = \frac{ ( 12 + 8.0 ) }{2} \times 4.0

\theta = 10 \times 4.0

\boxed {\theta = 40 \texttt{ rad}}

\texttt{ }

<em>Next , we could calculate the </em><em>average angular speed</em><em> as follows:</em>

\texttt{average angular speed} = \theta \div t

\texttt{average angular speed} = 40 \div 4.0

\boxed{\texttt{average angular speed} = 10 \texttt{ rad/s}}

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Moment of Inertia : brainly.com/question/13796477
  • The Ratio of the Moments of Inertia : brainly.com/question/2176655

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Rotational Dynamics

4 0
3 years ago
Read 2 more answers
Unpolarized light of intensity Io is incident on a stack of 7 polarizing filters, each with its axis rotated 17°cw with respect
mash [69]

The ratio of the intensity between light intensity that emerges from the last filter and unpolarized light of intensity, I₀ is It/I₀ = 0.2925

To answer the question, we need to know what polarization of light is.

<h3>What is polarization of light?</h3>

This is when the electric field vector of light is oscillating in one plane.

  • Now for light of intensity I' which is initially unpolarized, its intensity after polarization is I = 1/2I'.
  • Also, for light initially polarized, its intensity after polarization is I"' = I"cos²Ф where Ф is the angle between the initial direction and the direction of polarization.
<h3>Intensity of light through each polarized filter</h3>

Given that we have 7 polarizing filters, each rotated 17° cw with respect to the previous filter.

So, since the light is initially unpolarized,

  • The intensity through the first polarizing filter is I₁ = 1/2I₀ where I₀ is the initial intensity.
  • The intensity through the second polarizing filter is I₂ = I₁cos²17°= 1/2I₀cos²17°
  • The intensity through the third polarizing filter is I₃ = I₂cos²17° = 1/2I₀cos⁴17°
  • The intensity through the fourth polarizing filter is I₄ = I₃cos²17° = 1/2I₀cos⁶17°
  • The intensity through the fifth polarizing filter is I₅ = I₄cos²17° = 1/2I₀cos⁸17°
  • The intensity through the sixth polarizing filter is I₆ = I₅cos²17° = 1/2I₀cos¹⁰17°
  • The intensity through the seventh polarizing filter is I₇ = I₆cos²17° = 1/2I₀cos¹²17°.
<h3>The ratio of the intensity between light intensity that emerges from the last filter and unpolarized light of intensity</h3>

Since I₇ is the last intensity I₇ = It = 1/2I₀cos¹²17°.

So, It/I₀ = 1/2cos¹²17°

= 1/2(0.9563)¹²

= 1/2 × 0.5850

= 0.2925

So, the ratio of the intensity between light intensity that emerges from the last filter and unpolarized light of intensity, I₀ is It/I₀ = 0.2925

Learn more about intensity of polarized light here:

brainly.com/question/25402491

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Convert 26.4 mi to km
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Answer:

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Explanation:

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Two paths lead to the top of a big hill. One is steep and direct, while the other is twice as long but less steep. How much more
umka2103 [35]

Answer:

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