- One common use of a convex mirror is as shaving mirror.
- One common use of convex mirror is as rear-view mirrors in automobiles vehicles.
<h3>What is a
concave mirror?</h3>
A concave mirror is also referred to as a converging mirror and it can be defined as a type of mirror that is designed and developed with a reflective surface that is typically curved inward and away from the source of light.
Basically, one common use of a convex mirror include the following:
<h3>What is a
convex mirror?</h3>
A convex mirror is also referred to as a diverging mirror and it can be defined as a type of mirror that is designed and developed with a reflective surface that typically bulges outward toward the source of light.
Basically, one common use of convex mirror is as rear-view mirrors in automobiles vehicles.
Read more on convex mirror here: brainly.com/question/24175067
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<span>3.92 m/s^2
Assuming that the local gravitational acceleration is 9.8 m/s^2, then the maximum acceleration that the truck can have is the coefficient of static friction multiplied by the local gravitational acceleration, so
0.4 * 9.8 m/s^2 = 3.92 m/s^2
If you want the more complicated answer, the normal force that the crate exerts is it's mass times the local gravitational acceleration, so
20.0 kg * 9.8 m/s^2 = 196 kg*m/s^2 = 196 N
Multiply by the coefficient of static friction, giving
196 N * 0.4 = 78.4 N
So we need to apply 78.4 N of force to start the crate moving. Let's divide by the crate's mass
78.4 N / 20.0 kg
= 78.4 kg*m/s^2 / 20.0 kg
= 3.92 m/s^2
And you get the same result.</span>
Answer:
Yes labor is required therefor jobs like cashier, and other low skill labor jobs I'll not be required
Explanation:
Answer:
Let R1= resistance of 4ohms
R2= resistance of 8ohms
Equivalent resistance R will be
R=R1 + R2
=> 4+8=12ohms
The current through the two resistors will be the same since they are connected in series. Notwithstanding, the voltage will drop to appreciate the change.
Explanation:
Answer:
y = 52.44 10⁻⁶ m
Explanation:
It is Rayleigh's principle that two points are resolved if the maximum of the diffraction pattern of one matches the minimum the diffraction pattern of the other
Based on this principle we must find the angle of the first minimum of the diffraction expression
a sin θ= m λ
The first minimum occurs for m = 1
sin θ = λ / a
Now let's use trigonometry the object is a distance L = 0.205 m
tan θ = y / L
Since the angles are very small, let's approximate
tan θ = sin θ/cos θ = sin θ
sin θ = y / L
We substitute in the diffraction equation
y / L = λ / a
y = λ L / a
Let's calculate
y = 550 10⁻⁹ 0.205 / 2.15 10⁻³
y = 52.44 10⁻⁶ m
