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3 years ago

On a warm sunny day, a deer is searching something to drink. The deer is most likely responding to which kind of stimulus?

Chemistry

2 answers:

storchak [24]3 years ago

7 0

Answer:

your answer is: the external stimulus of thirst

Explanation:

I took the test :)) hope this helps!!!!!!

quester [9]3 years ago

4 0

Answer:

External stimulus of thirst

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Balance the equation of. _C + _O2 -- _CO

scoundrel [369]

Explanation:

2C +O2 = 2CO

this will be the answer

8 0

2 years ago

What causes the Brownian motion of particles in a colloid?

LekaFEV [45]

Answer:

The correct answer option is a) collisions between the particles and surrounding molecules.

Explanation:

The collisions between the particles and surrounding molecules causes the Brownian motion of particles in a colloid.

Brownian motion is the irregular movement of the microscopic particles in a fluid which bombard into each other.

It basically is the result of the molecules of a dispersion medium colliding with the dispersed particles of the phase.

6 0

2 years ago

Given the following information: Mass of proton = 1.00728 amu Mass of neutron = 1.00866 amu Mass of electron = 5.486 × 10^-4 amu

lesya692 [45]

Answer: The nuclear binding energy of the given element is $2.938\times 10^{12}J/mol$

Explanation:

For the given element $_3^6\textrm{Li}$

Number of protons = 3

Number of neutrons = (6 - 3) = 3

We are given:

$m_p=1.00728amu\\m_n=1.00866amu\\A=6.015126amu$

M = mass of nucleus = $(n_p\times m_p)+(n_n\times m_n)$

$M=[(3\times 1.00728)+(3\times 1.00866)]=6.04782amu$

Calculating mass defect of the nucleus:

$\Delta m=M-A\\\Delta m=[6.04782-6.015126)]=0.032694amu=0.032694g/mol$

Converting this quantity into kg/mol, we use the conversion factor:

1 kg = 1000 g

So, $0.032694g/mol=0.032694\times 10^{-3}kg/mol$

To calculate the nuclear binding energy, we use Einstein equation, which is:

$E=\Delta mc^2$

where,

E = Nuclear binding energy = ? J/mol

$\Delta m$ = Mass defect = $0.032694\times 10^{-3}kg/mol$

c = Speed of light = $2.9979\times 10^8m/s$

Putting values in above equation, we get:

$E=0.032694\times 10^{-3}kg/mol\times (2.9979\times 10^8m/s)^2\\\\E=2.938\times 10^{12}J/mol$

Hence, the nuclear binding energy of the given element is $2.938\times 10^{12}J/mol$

3 0

3 years ago

Question 4 (4 points)

Fiesta28 [93]

I don’t know what is your problem

7 0

3 years ago

Select all the correct answers. Why do real gases not behave exactly like ideal gases? Real gases are always hotter than ideal g

Lemur [1.5K]

Answer:

See below.

Explanation:

1. Real gases have significant volume.

2. Real gases have more complex interactions than ideal gases.

4 0

3 years ago