Answer:
0.015 m/s2
Explanation:
Using Newtons 2nd law.
F = ma where F = Force applied, m = mass of the object and a = acceleration acquired.
So substitute the values in SI units.
m = 
kg
Therefore F = 0.003×5 = 0.015 m/s2
<span><span>Imagine we have a 2 lb ball of putty moving with a speed of 5 mph striking and sticking to a 18 lb bowling ball at rest; the time it takes to collide is 0.1 s. After the collision, the two move together with a speed of v1. To find v1, use momentum conservation: 2x5=(18+2)v1, v1=0.5 mph. </span><span>Next, imagine we have a 18 lb bowling ball moving with a speed of 5 mph striking and sticking to a 2 lb ball of putty at rest; the time it takes to collide is 0.1 s. After the collision, the two move together with a speed of v2. To find v2, use momentum conservation: 18x5=(18+2)v2, v2=4.5 mph. </span><span>
</span><span>
</span><span>now figure out your problem its really easy let me know if you need more help </span></span>
Answer:
Increasing the speed of an object decreases its motion energy. Increasing the speed of an object increases its motion energy. Increasing the speed of an object does not affect its motion energy. Whether or not its motion energy is affected depends on how much its speed was increased.
Explanation:
Answer:
60Watts
Explanation:
Given parameters:
Current = 0.5A
Voltage = 120V
Unknown
Power = ?
Solution:
The power in the electric circuit is the product of current and voltage;
P = IV
Insert the given parameters and solve;
P = 0.5 x 120
P = 60Watts
Answer:
735 J
Explanation:
From the question given above, the following data were obtained:
Weight (W) = 49 N
Height (h) = 15 m
Potential energy =?
Potential energy is simply defined as the product of weight of the object and height to which the object is raised. Mathematically, it is expressed as:
Potential energy = weight × height
With the above formula, we can obtain the potential energy of the coconut as follow:
Weight (W) = 49 N
Height (h) = 15 m
Potential energy =?
Potential energy = weight × height
Potential energy = 49 × 15
Potential energy = 735 J
Thus, the potential energy of the coconut is 735 J
