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dlinn [17]
3 years ago
14

Mike walked 450 m west. He then turned and walked 150 m to the east in 300 seconds. what was his velocity?

Physics
2 answers:
enyata [817]3 years ago
8 0
Velocity = Displacement / time

Displacement = 450 - 150 = 300.

By the time he walked 150 East, he walked backwards. Hence displacement is 300 m West.

Velocity = 300m / 300 s
  
              = 1 m/s
Sindrei [870]3 years ago
7 0

Answer:

Velocity, v = 1 m/s

Explanation:

Given that,

Initially Mike walked 450 m due west and then he turned and walked 150 m to the east.

Time taken, t = 300 s

The displacement of Mike is equal to the difference in final position and the initial position.

d = 450 - 150

d = 300 m

Let v is his velocity. It is equal to the net displacement divided by total time taken.

v=\dfrac{d}{t}

v=\dfrac{300\ m}{300\ s}

v = 1 m/s

So, the velocity of Mike is 1 m/s. Hence, this is the required solution.

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Answer:

The value is w= 2*10^{-3} \  rad/s

Explanation:

From the question we are told that

  The diameter of the storm is  d =  10.0 \  km  =  10 000 \  m

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Generally the radius is mathematically represented as

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=>  r =  \frac{10000}{2}

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Generally the angular velocity is mathematically represented as  

        w= \frac{v}{r}

=>     w= \frac{10}{5000}

=>     w= 2*10^{-3} \  rad/s

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Explanation:

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We start by analyzing the vertical motion: we can find the time of flight of the ball by using the following suvat equation

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Solving for t,

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Now we analyze the horizontal motion. We know that the ball covers a horizontal distance of

d = 0.50 m

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t = 0.495 s

Therefore, since the horizontal velocity is constant, we can calculate it as

v_x = \frac{d}{t}=\frac{0.50}{0.495}=1.01 m/s

So, the ball rolls off the table at 1.01 m/s.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

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