Mike walked 450 m west. He then turned and walked 150 m to the east in 300 seconds. what was his velocity?
2 answers:
Answer:
Velocity, v = 1 m/s
Explanation:
Given that,
Initially Mike walked 450 m due west and then he turned and walked 150 m to the east.
Time taken, t = 300 s
The displacement of Mike is equal to the difference in final position and the initial position.
d = 450 - 150
d = 300 m
Let v is his velocity. It is equal to the net displacement divided by total time taken.
v = 1 m/s
So, the velocity of Mike is 1 m/s. Hence, this is the required solution.
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Answer:
1.72 x 10³ N.
Explanation:
When a charge is split equally and placed at a certain distance , maximum electrostatic force is possible.
So the charges will be each equal to
31/2 = 15.5 x 10⁻⁶ C
F = K Q q / r²
=
= 1.72 x 10³ N.
a) 120 s
b) v = 0.052R [m/s]
Explanation:
a)
The period of a revolution in a simple harmonic motion is the time taken for the object in motion to complete one cycle (in this case, the time taken to complete one revolution).
The graph of the problem is missing, find it in attachment.
To find the period of revolution of the book, we have to find the time between two consecutive points of the graph that have exactly the same shape, which correspond to two points in which the book is located at the same position.
The first point we take is t = 0, when the position of the book is x = 0.
Then, the next point with same shape is at t = 120 s, where the book returns at x = 0 m.
Therefore, the period is
T = 120 s - 0 s = 120 s
b)
The tangential speed of the book is given by the ratio between the distance covered during one revolution, which is the perimeter of the wheel, and the time taken, which is the period.
The perimeter of the wheel is:
where R is the radius of the wheel.
The period of revolution is:
Therefore, the tangential speed of the book is:
