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3 years ago

What is the IUPAC name of the following compound?

Chemistry

1 answer:

inn [45]3 years ago

7 0

Answer:

2,6–dimethylcyclohexanol

Explanation:

To name the compound given in the question above, we must first obtain the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain.

3. Identify the substituent group attached to the compound.

4. Locate the position of the substituent group.

5. Combine the above to obtain the name of the compound.

Now, we shall determine the name IUPAC name of the compound. This can be obtained as follow:

1. The compound contains the –OH group. Thus, the compound is an alcohol.

2. The compound is a cyclic compound with six carbon forming the ring. Thus, the parent name of the compound is cyclohexane. Thus, the presence of the –OH group changes the parent name of the compound to cyclohexanol.

3. The substituent group attached to the compound is methyl (–CH₃)

NOTE: There are two –CH₃ groups attached to the compound.

4. The position of the 1st –CH₃ group is at carbon 2, while the 2nd is at carbon 6.

NOTE: Counting is done from the carbon bearing the functional group.

5. Therefore, the name of the compound is:

2,6–dimethylcyclohexanol

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Iron (III) oxide and hydrogen react to form iron and water, like this:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound Amount

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Answer: The value of equilibrium constant for given equation is $1.0\times 10^{-4}$

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

For hydrogen gas:

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M$

For water:

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M$

For the given chemical equation:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression of equilibrium constant for above equation follows:

$K_{eq}=\frac{[H_2O]^3}{[H_2]^3}$

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}$

Hence, the value of equilibrium constant for given equation is $1.0\times 10^{-4}$

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