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Neporo4naja [7]
3 years ago
9

What is the IUPAC name of the following compound?

Chemistry
1 answer:
inn [45]3 years ago
7 0

Answer:

2,6–dimethylcyclohexanol

Explanation:

To name the compound given in the question above, we must first obtain the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain.

3. Identify the substituent group attached to the compound.

4. Locate the position of the substituent group.

5. Combine the above to obtain the name of the compound.

Now, we shall determine the name IUPAC name of the compound. This can be obtained as follow:

1. The compound contains the –OH group. Thus, the compound is an alcohol.

2. The compound is a cyclic compound with six carbon forming the ring. Thus, the parent name of the compound is cyclohexane. Thus, the presence of the –OH group changes the parent name of the compound to cyclohexanol.

3. The substituent group attached to the compound is methyl (–CH₃)

NOTE: There are two –CH₃ groups attached to the compound.

4. The position of the 1st –CH₃ group is at carbon 2, while the 2nd is at carbon 6.

NOTE: Counting is done from the carbon bearing the functional group.

5. Therefore, the name of the compound is:

2,6–dimethylcyclohexanol

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Heat transfer is the phenomenon that occurs when the two objects are in the vicinity of each other and by increasing the area of their contact. Thus, option B is correct.

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Select the answer that CANNOT be used to fill in the blank in the following sentence:
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the answer is ur mom

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8 0
3 years ago
How much heat is evolved in converting 1.00 mol of steam at 155.0 ∘c to ice at -50.0 ∘c? the heat capacity of steam is 2.01 j/(g
Ne4ueva [31]
When the specific heat capacity of the water is 4.18 J/g.°C so, we are going to use this formula to get the heat for cooling three  phases changes from steam to liquid and from liquid to ice (solid) :

when Q = M*C*ΔT 

Q is the heat in J

and M is the mass in gram = 1 mol H2O * 18 g/mol(molar mass) = 18 g

C is the specific heat J/g.°C

ΔT is the change in temperature

Q = Mw *[ ( Csteam * ΔTsteam)+(Cw*ΔTw) + (Cice  * ΔT ice)]

    = 18 g * [(2.01 * (155-100°C)) + (4.18 * (100-0°C)) + (2.09 * (0 - 55 °C))]

∴Q = 7444.8 J

and when we know that the heat of fusion for water = 334J/g

and heat of vaporization for water =  2260J/g


∴Q for the two phases changes = M * (2260+334) 

                                                      = 18 * (2260+334)

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5 0
3 years ago
A sample of nitrogen is initially at a pressure of 1.7 kPa, a temperature of -10 C and a volume of 7.5 m3. Then the volume is de
zhannawk [14.2K]

Answer:

\boxed{\text{2.6 kPa}}

Explanation:

To solve this problem, we can use the Combined Gas Laws:

\dfrac{p_{1}V_{1} }{T_{1}} = \dfrac{p_{2}V_{2} }{T_{2}}

Data:

p₁ = 1.7 kPa; V₁ = 7.5 m³;  T₁ =   -10 °C

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(b) Calculate the pressure

\begin{array}{rcl}\dfrac{1.7 \times 7.5 }{263.15} & = & \dfrac{p_{2} \times 3.8}{200}\\\\0.0485 & = & 0.0190p_{2}\\p_{2} & = & \textbf{2.6 kPa}\\\end{array}\\\text{The new pressure of the gas is \boxed{\textbf{2.6 kPa}}}

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