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3 years ago

Which of the following nuclei would be the least stable

Chemistry

2 answers:

Nikitich [7]3 years ago

8 0

<h2>Answer:</h2>

The nuclei with <u>D. 1 proton and 2 neutrons</u> will be least stable.

<h2>Explanation:</h2>

Nuclides containing odd quantities of the two protons and neutrons are the least steady and this implies increasingly radioactive.

Nuclides containing even quantities of the two protons and neutrons are most steady and this implies less radioactive.

Nuclides contain odd quantities of protons (positive charged particles) and even quantities of neutrons are less steady than nuclides which are containing even quantities of protons and odd quantities of neutrons. By and large, atomic strength is more prominent for nuclides containing even quantities of protons and neutrons or both.

When we add 1 proton with 2 neutrons we get 3 as answer, which means an odd value, thus nuclide with this proportion of proton and neutron is least stable.

Brut [27]3 years ago

6 0

Answer:

C. 1 proton 3 neutrons

Explanation:

A nucleus is more stable if the ratio of the neutrons to protons is between 1:1 and 1:1.5.

Thus the ratios of neutrons to protons for the nuclei are as follows

A- 1:1

B- 1:1

C- 1:3

D- 1:2

Among these ratios, C is the greatest thus the nucleus is the least stable.

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1 year ago

What is the molar mass of C4H10

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3 years ago

an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem

OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

$P\cdot V = n\cdot R\cdot T$ ,

$\displaystyle V = \frac{n\cdot R\cdot T}{P}$ .

where

$P$ is the pressure of the gas,
$V$ is the volume of the gas,
$n$ is the number of moles of particles in this gas,
$R$ is the ideal gas constant, and
$T$ is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of $R$ will be $8.314$ if $P$ , $V$ , and $T$ are in SI units. Convert these values to SI units:

$P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa$ ;
$V$ shall be in cubic meters, $\rm m^{3}$ ;
$T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K$ .

Apply the ideal gas law:

$\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}$ .

4 0

3 years ago