All categories

3 years ago

A dump truck contains a load of soil. Which action will leave the dump truck's

Physics

2 answers:

antoniya [11.8K]3 years ago

5 0

D ) increase the force applied by the engine

soldier1979 [14.2K]3 years ago

3 0

Answer:

Explanation:

This will not change the weight and therefore not change the inertia

You might be interested in

The gas in a cylinder has a volume of 8 liters at a pressure of 109 kPa. The pressure of the gas is increased to 211 kPa. Assumi

user100 [1]

3.9 L I believe

I hope this helps!

4 0

3 years ago

A rotating cylinder about 16 km long and 7.8km in diameter is designed to be used as a space colony.

Semmy [17]

Answer:

0.05 rad/s

Explanation:

7.8 km = 7800 m

For the residents inside the space cylinder to experience the same gravitation acceleration g = 9.81m/s2 on Earth, the centripetal acceleration must be the same as g

$a = g$

But centripetal acceleration is product of angular velocity squared and radius of rotation r

$\omega^2r = 9.81$

$\omega^2 d/2 = 9.81$

$\omega^2 = \frac{2*9.81}{d} = \frac{19.62}{7800} = 0.0025$

$\omega = \sqrt{0.0025} = 0.05 rad/s$

3 0

3 years ago

A 300 kg block of dimensions 1.5 m × 1.0 m × 0.5 m lays on the table with its largest face.

netineya [11]

Answer:

1.5

x 1.0

1.50

x 0.5

075.00

answer: 75.00m

Explanation:

I hope this help

7 0

3 years ago

3. Order the following lengths from shortest to longest.

horrorfan [7]

Answer: $d < a < c < b$

$3.3 cm < 400 mm < 170 m < 22 km$

Explanation:

Firstly, let's convert these length to meters $m$ , in order to work with the same units:

a. 400 millimeters

$400 mm \frac{1m}{1000 mm}=0.4 m$

b. 22 kilometers

$22 km \frac{1000m}{1 km}=22000 m$

c. 170 meters

Here the lenght is already in meters

d. 3.3 centimeters

$3.3 cm \frac{1m}{100 cm}=0.033 m$

Now that we have all the lengths in meters, we can order them from shortest to longest:

$0.033 m < 0.4 m < 170 m < 22000 m$

$d < a < c < b$

7 0

4 years ago

If a 110 kg go-cart traveling at a velocity of 13.41 m/s has a collision with an impulse of 615 Nxs, what is the

mafiozo [28]

Answer:

5.59 m/s

Explanation:

We are given;

Mass = 110 kg

Initial velocity: u = 13.41 m/s

Force = 615 N

Time(t) = 1 s

Now, the formula for force is;

Force = mass x acceleration

Thus;

615 = 110 × acceleration

\Acceleration(a) = 615/110 = 5.591 m/s²

Now, using Newton's first law of motion, we can find acceleration (a). Thus;

v = u + at

v = 13.41 + (5.591 × 1)

v ≈ 19 m/s

So,the change in velocity is;

Final velocity(v) - Initial velocity(u) = 19 - 13.41 = 5.59 m/s

6 0

3 years ago