All categories

2 years ago

A dump truck contains a load of soil. Which action will leave the dump truck's

Physics

2 answers:

antoniya [11.8K]2 years ago

5 0

D ) increase the force applied by the engine

soldier1979 [14.2K]2 years ago

3 0

Answer:

Explanation:

This will not change the weight and therefore not change the inertia

You might be interested in

Which one of the following temperatures (in °C) is equivalent to 294 K?

vaieri [72.5K]

Answer:

Explanation: its actually 20.85 but i guess they round to 21

5 0

2 years ago

A spherical balloon has a radius of 6.95 m and is filled with helium. The density of helium is 0.179 kg/m3, and the density of a

Aleks [24]

volume of balloon

= 4/3 T R3

= 4/3 x 3.14 x 6.953

= 1405.47 m3

uplift force

= volume of balloon x density of air x 9.8

= = 1405.47 x 1.29 x 9.8

= 1813.05 x 9.8 N

weight of helium gas

= volume of balloon x density of helium x

9.8

= 1405.47 x .179 x 9.8

= 251.58 x 9.8 N

Weight of other mass = 930 x 9.8 N Total weight acting downwards

= 251.58 x 9.8 +930 x 9.8

= 1181.58 x 9.8 N

If W be extra weight the uplift can balance

1181.58 × 9.8 + W × 9.8 = 1813.05 * 9.8

1181.58+W=1813.05

W= 631.47 kg

3 0

2 years ago

What is the relationship between lightning and atoms

Rufina [12.5K]

Answer:

The answer is A

Explanation:

Lightning is formed by electrons in the air

6 0

2 years ago

How does wavelength change as frequency increases? A) Wavelength increases as frequency increases. B) Wavelength decreases as fr

ValentinkaMS [17]

Wavelength decreases as frequency increases

8 0

2 years ago

Read 2 more answers

An object 5.Ocm in the length is placed at a distance of 20cm in front of convex mirror

andrew-mc [135]

Answer:

Position = $\frac{60}{7}\ cm$ behind the mirror

Nature = Virtual and Erect

Size = $\frac{15}{7}\ cm$ : Diminished

Explanation:

Sign convention-Distance measured to the left of pole is negative and to the right of pole is positive.

Object distance = u = -20 cm

Focal length = f = Radius of curvature/2 = 30/2 = 15 cm

We have to use mirror formula to find image distance.

$\frac{1}{u}+\frac{1}{v}=\frac{1}{f}\\ \frac{1}{-20}+\frac{1}{v}=\frac{1}{15}\\ \frac{1}{v}=\frac{7}{60}\\v=\frac{60}{7}\ cm$

Since the image distance is positive, it is formed behind the mirror or a virtual image is formed.

Magnification = $=\frac{h_{image}}{h_{object}}=$ $-\frac{v}{u}=\frac{60}{7\times20}=\frac{3}{7}$

Height of the object = 5 cm

Height of the image = $5\times\frac{3}{7}=\frac{15}{7}\ cm$

Since the height of the image is positive and less than the size of object,it is erect and diminished.

4 0

3 years ago