Divide 1.2 by 72 to get the wattage of one beat.
1.2/ 72 = .016666...
terminate by rounding up, giving you .0167kW
Answer:
15 deg
Explanation:
Assume both snowballs are thrown with the same initial speed 27.2 m/s. The first snowball is thrown at an angle of 75◦ above the horizontal. At what angle should you throw the second snowball to make it hit the same point as the first? The acceleration of gravity is 9.8 m/s 2 . Answer in units of ◦ .
Given:
For first ball, θ1 = 75◦
initial velocity for both the balls, u = 27.2 m/s
for second ball, θ2 = ?
since distance covered by both the balls is same.
Therefore,..
R1=(u^{2} sin2\alpha _{1}) /g[/tex]
the range for the first ball
the range for the second ball
R2=(u^{2} sin2\alpha _{2}) /g[/tex]
(u^{2} sin2\alpha _{2}) /g[/tex]=(u^{2} sin2\alpha _{1}) /g[/tex]
sin2\alpha _{2})=sin2\alpha _{1})
=sin^-1(sin2\alpha _{1})
=1/2sin^-1(sin2\alpha _{1})
=
15 deg
Answer:
speed of molecule ∝ 1/mass of molecule.
Explanation:
The velocities of the molecules depend on their masses. That's because if the molecules are large in size, their velocity is slower. Therefore their velocity is quicker when their size is small, since the molecules can move faster.
Therefore , it can be written as
speed of molecule ∝ 1/mass of molecule.
Answer:
The displacement of the boat is 7.41 m
Explanation:
Given;
initial velocity of the motorboat, u = 6.5 m/s west
final velocity of the motorboat, v = 1.5 m/s west
acceleration of the motorboat, a = -2.7 m/s² east
The displacement of the boat is given by;
v² = u² + 2ad
where;
d is the displacement of the motorboat
1.5² = 6.5² + 2(-2.7)d
1.5² - 6.5² = -5.4d
-40 = -5.4d
d = (40) / 5.4
d = 7.41 m
Therefore, the displacement of the boat is 7.41 m
