A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the
1 answer:
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Answer: Trajectory=51m
Displacement=41m
Explanation:
Let's begin by stating clear that <u>movement is the change of position of a body at a certain time.</u> So, during this movement, the body will have a trajectory and a displacement, being both different:
The trajectory is the path followed by the body (is a scalar magnitude).
The displacement is the distance in a straight line between the initial and final position (is a vector magnitude).
According to this, in the description of the object placed at x= -7m on a number line and moving some 12m to the left and then to the right, stopping at x=34m; we are talking about the path followed by the object, hence its <u>trajectory</u>. So, 51 m is its trajectory.
But, if we talk about displacement, we have to draw a straight line between the initial position of the object (x=-7m) to its final position (x=+34m).
Now, being this an unidimensional problem, the displacement vector for this object is 41m.
Answer: (2) Use the Momentum Principle.
Explanation:
In fact, it is called the <u>Conservation of linear momentum principle,</u> which establishes the initial momentum of the asteroids before the collision must be equal to the final momentum
after the collision, no matter if the collision was elastic or inelastic (in which the kinetic energy is not conserved).
In this sense, the linear momentum of a body is defined as:
Where is the mass and
the velocity.
Therefore, the useful approach in this situation is<u> option (2)</u>.