Answer:
1.48 kg
Explanation:
mass of copper = 4 kg
Decrease in temperature of copper = 36.9°C
increase in temperature of water = 9.20°C
Let the mass of water is m.
Specific heat of water = 4181 J/Kg°C
Specific heat of copper = 385 J/kg°C
According to the principle of caloriemetery
Heat lost by copper = heat gained by water
mass of copper x specific heat of copper x decrease in temperature = mass of water x specific heat of water x increase in temperature
4 x 385 x 36.9 = m x 4181 x 9.20
56826 = 38465.2 m
m = 1.48 kg
Thus, the mas of water is 1.48 kg.
mas of water
W = mg, Assuming g ≈ 9.8 m/s² on the earth surface.
735 N = m* 9.8
735/9.8 = m
75 = m
Mass , m = 75 kg. B.
Answer:
(b) 490 N downwards
Explanation:
(b) Formula : w= mg
m is the mass of the object
g is a gravitational constant (9.8)
w= mg
= 50×9.8
= 490 N downwards
When the child jumps onto the merry-go-around the moment of inertia of the system changes. If we consider the child to be point-like mass then its moment of inertia would be:

We get the new moment of inertia by simply adding the child's moment of inertia to the old moment of inertia.

Since there is no force mention we must assume that angular momentum is conserved.

When we plug in all the numbers we get:
The speed of the water in the wider part will be 1.194 m/sec. Speed is a time-based quantity. Its SI unit is m/sec.
<h3> What is speed?</h3>
Speed is defined as the rate of change of the distance or the height attained.
The given data in the problem is;
The initial diameter is,
initial radius,

The initial crossection area;

The final crossection area;

The initial flow rate is;
R = density ×velocity ×area

The speed of the water in the wider part will be;
From the continuity equation;

Hence, the speed of the water in the wider part will be 1.194 m/sec.
To learn more about the speed, refer to the link;
brainly.com/question/7359669
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