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yuradex [85]
3 years ago
5

How many significant figures are in 0.0067?

Physics
1 answer:
larisa [96]3 years ago
3 0

Answer:

2

Explanation:

there are 2 significant figures in there

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Consider two copper wires of the same length. One has twice the cross-sectional area of the other. How do the resistances of the
JulsSmile [24]

Answer: a) when the cross section is doubled the resultant resistence  is a half. This means the thicker wire have half resistence than the thinner wire.

Explanation: In order to explain this behaviur we have to consider the expresion for the resistence which is given by:

R=\frac{\epsilon o  L}{A} where L and A are the length and the cross section for the wire, respectively.

From this expresssion we can conclude the above, this means

R=εo*L/A  if A is now 2A we have

R' = εo*L/2*A= R/2

6 0
3 years ago
2. Which of the following is not a macromolecule?
svlad2 [7]

Answer:

C

Explanation:

5 0
4 years ago
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4 0
3 years ago
The mass of the Moon is 7.35 x 1022 kg, while that of Earth is 5.98 x 1024 kg. The average distance from the center of the Moon
Kryger [21]

Answer:

aaa

Explanation:

m_e = Mass of the Earth =  5.98 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r_1 = Distance from the center of the Moon to the center of Earth = 6371000 m

r_2 = Distance from the center of the earth center to sun center

m_m = Mass of moon = 7.35\times 10^{22}\ kg

M = Mass of sun = 1.989\times 10^{30}\ kg

F_1=G\frac{m_em_m}{r_1^2}\\\Rightarrow F_1=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 7.35\times 10^{22}}{(384000000)^2}\\\Rightarrow F_1=1.988\times 10^{20}\ N

F_2=G\frac{Mm_e}{r_1^2}\\\Rightarrow F_2=6.67\times 10^{-11}\frac{5.98\times 10^{24}\times 1.989\times 10^{30}}{(149.6\times 10^9+6371000+695.51\times 10^6)^2}\\\Rightarrow F_2=3.511\times 10^{22} N

\frac{F_1}{F_2}=\frac{1.988\times 10^{20}}{3.511\times 10^{22}}\\\Rightarrow \frac{F_1}{F_2}=0.00566\\\Rightarrow F_1=F_20.00566

Hence the force of moon on earth is 0.00566 times the force of earth on moon center to center

4 0
4 years ago
I am trying to find the magnitude of a resultant vector. Do i take inconsideration the negatives when i find the x & y compo
attashe74 [19]
Absolutely !  If you have two vectors with equal magnitudes and opposite
directions, then one of them is the negative of the other.  Their correct
vector sum is zero, and that's exactly the magnitude of the resultant vector.

(Think of fifty football players pulling on each end of the rope in a tug-of-war. 
Their forces are equal in magnitude but opposite in sign, and the flag that
hangs from the middle of the rope goes nowhere, because the resultant
force on it is zero.)

This gross, messy explanation is completely applicable when you're totaling up
the x-components or the y-components.
4 0
4 years ago
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