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Nadusha1986 [10]
3 years ago
12

In a paragraph of 125 words, distinguish the engineering design process from the reverse engineering process, citing at least th

ree differences.
Engineering
2 answers:
Yuki888 [10]3 years ago
7 0

The difference between the engineering design process and the reverse engineering process are there, but very subtle. The engineering design process is a process based on careful planning and months of designing to create a blueprint for a certain project. The reverse engineering process is the base of learning to create something by working backwards on a previously made inspiration for your project. Three differences are that that the engineering design process doesn't require any physical learning and is more based on mental and written learning (unlike the reverse engineering process). Another difference includes that in the reverse engineering process you don't need to take anything apart and learn how things work based on the on hands aspect of this variety of engineering. The final difference is that the engineering design project is made fresh from your own thoughts and not based off of a similar project.

ch4aika [34]3 years ago
3 0

Answer:

The correct answer will explain that the engineering design process begins with a specific need, including the specifications and limitations of a design. If a current product or object does not match the need, then engineers will create a new design. The purpose of the engineering design process is to create or improve a design. Reverse engineering is more of an exploratory process, without the need to create a product that fits limitations and specifications. The reverse engineering process does not necessarily seek to improve a design so much as to understand the design. The key actions in this process include analyzing the structure and functions for the goal of recreating the same or similar functions. To determine which process to use, the engineer must identify his or her project goals.

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A 0.91 m diameter corrugated metal pipe culvert (n = 0.024) has a length of 90 m and a slope of 0.0067. The entrance has a squar
NikAS [45]

Answer:

HW=1.71m

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

3 0
3 years ago
What is the difference between the pressure head at the end of a 150m long pipe of diameter 1m coming from the bottom of a reser
uysha [10]

Answer:

\frac {p_2- p_1}{\rho g} = 31.06 m

Explanation:

from bernoulli's theorem we have

\frac{p_1}{\rho g} + \frac{v_1^{2}}{2g} +z_1 = \frac{p_2}{\rho g} + \frac{v_2^{2}}{2g} +z_2  + h_f

we need to find pressure head difference i.e.

\frac {p_2- p_1}{\rho g} = (z_1 - z_2) - h_f

where h_f id head loss

h_f = \frac{flv^{2}}{D 2g}

velocity v =\frac{1}{n} * R^{2/3} S^{2/3}

S = \frac{\delta h}{L} = \frac{40}{150} = 0.267

hydraulic mean radius R =\frac{A}{P} = \frac{hw}{2h+w}

R = \frac{40*1}{2*40+1} = 0.493 m

so velocity is  =\frac{1}{0.013} * 0.493^{2/3} 0.267^{1/2}

v = 24.80 m/s

head loss

h_f = \frac{0.0019*150*24.80^{2}}{1* 2*9.81}

h_f  =8.93 m

pressure difference is

\frac {p_2- p_1}{\rho g} = 40 - 8.93 = 31.06 m

\frac {p_2- p_1}{\rho g} = 31.06 m

4 0
3 years ago
If the bolt head and the supporting bracket are made of the same material having a failure shear stress of 'Tra;i = 120 MPa, det
Nina [5.8K]

Answer:

P=361.91 KN

Explanation:

given data:

brackets and head of the screw are made of material with T_fail=120 Mpa

safety factor is F.S=2.5

maximum value of force P=??

<em>solution:</em>

to find the shear stress

                            T_allow=T_fail/F.S

                                         =120 Mpa/2.5

                                         =48 Mpa

we know that,

                               V=P

<u>Area for shear head:</u>

                              A(head)=π×d×t

                                           =π×0.04×0.075

                                           =0.003×πm^2

<u>Area for plate:</u>

                               A(plate)=π×d×t  

                                            =π×0.08×0.03

                                            =0.0024×πm^2

now we have to find shear stress for both head and plate

<u>For head:</u>

                                   T_allow=V/A(head)

                                    48 Mpa=P/0.003×π                 ..(V=P)

                                             P =48 Mpa×0.003×π

                                                =452.16 KN

<u>For plate:</u>

                                   T_allow=V/A(plate)

                                    48 Mpa=P/0.0024×π                 ..(V=P)

                                             P =48 Mpa×0.0024×π

                                                =361.91 KN

the boundary load is obtained as the minimum value of force P for all three cases. so the solution is

                                                P=361.91 KN

note:

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7 0
3 years ago
At what stage of development is an engineering team the most productive?
Alexxx [7]

Answer:

A

Explanation:

A because you are continuing to keep moving and thinking.

3 0
2 years ago
Read 2 more answers
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swat32

The first thing you should do is develop a <u>budget</u> to determine what vehicle you can afford.

<h3>What is an automobile?</h3>

An automobile is also referred to as a vehicle, car or motorcar and it can be defined as a four-wheeled vehicle that is designed and developed to be propelled by an internal-combustion (gasoline) engine, especially for the purpose of transportation from one location to another.

<h3>What is a budget?</h3>

A budget can be defined as a financial plan that is typically used for the estimation of revenue and expenditures of an individual, business organization or government for a specified period of time, often one year.

In this context, we can reasonably infer and logically deduce that the first thing anyone should do is to develop a <u>budget</u> in order to determine what vehicle they can afford.

Read more on budget here: brainly.com/question/13964173

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