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Nadusha1986 [10]
3 years ago
12

In a paragraph of 125 words, distinguish the engineering design process from the reverse engineering process, citing at least th

ree differences.
Engineering
2 answers:
Yuki888 [10]3 years ago
7 0

The difference between the engineering design process and the reverse engineering process are there, but very subtle. The engineering design process is a process based on careful planning and months of designing to create a blueprint for a certain project. The reverse engineering process is the base of learning to create something by working backwards on a previously made inspiration for your project. Three differences are that that the engineering design process doesn't require any physical learning and is more based on mental and written learning (unlike the reverse engineering process). Another difference includes that in the reverse engineering process you don't need to take anything apart and learn how things work based on the on hands aspect of this variety of engineering. The final difference is that the engineering design project is made fresh from your own thoughts and not based off of a similar project.

ch4aika [34]3 years ago
3 0

Answer:

The correct answer will explain that the engineering design process begins with a specific need, including the specifications and limitations of a design. If a current product or object does not match the need, then engineers will create a new design. The purpose of the engineering design process is to create or improve a design. Reverse engineering is more of an exploratory process, without the need to create a product that fits limitations and specifications. The reverse engineering process does not necessarily seek to improve a design so much as to understand the design. The key actions in this process include analyzing the structure and functions for the goal of recreating the same or similar functions. To determine which process to use, the engineer must identify his or her project goals.

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The rate of flow through an ideal clarifier is 8000m3 /d, the detention time is 1h and the depth is 3m. If a full-length movable
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a) 35%

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depth = 3m

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= 3 / 1 = 3m/h

The percent removal of particles having a settling velocity of 1m/h ≈ 35%

<u>b) Determine if  the removal efficiency of the clarifier can be improved by moving the tray, the location of the tray  and the maximum removal efficiency</u>

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= ( d_{a},v_{p} ) . \frac{d_{a} }{depth}  + ( d_{a},v_{p} ) . \frac{depth - d_{a} }{depth}  = 100

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<u>c) what is the effect of moving the tray would be if the particle settling velocity were equal to 0.5m/h?</u>

The maximum removal will drop as the particle settling velocity = 0.5 m/h

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