The magnetic fields of magnets are most powerful at the <u>poles of a magnet</u>. Without any difference in the magnitude, both the poles have equal amount of Magnetic field intensity at their poles.
If you see the field lines we can see the field lines start from the North Pole run parallel and end at the South Pole. The field lines are concentrated more at the poles hence the magnetic field intensity or the magnetic field itself is more at the poles than any other part.
<h3><u>Answer;</u></h3>
<em>too small to be seen with an optical microscope </em>
<h3><u>Explanation;</u></h3>
- <em><u>An electron microscope is a type of microscope that is used to observe very tiny specimens whose features can not be observed by other types of microscopes.</u></em> It uses a beam of electrons to generate an image of a given specimen whose features can be clearly observed and studied.
- <em><u>Electron microscope has very high resolution and magnification as compared to other optical microscope </u></em>hence can be observed in the study of micro-organisms such as viruses which would be difficult to study their features using optical microscopes.
Answer:
Using the range formula R = v^2 sin 2 theta / g
or v^2 = R * g / sin 86.4
v^2 = 3.14 m * 9.81 m/s2 / .998
v^2 = 30.9 m^2 / s^2
v = 5.56 m/s
This hasn't really proved the question - this would give
vy = 5.56 * sin 43.2 = 3.81 m/s
vx = 5.56 * cos 43.2. = 4.05 m/s
t = 1.57 / 4.05 = .387 sec to reach the waterfall
h = 3.81 * .387 - 4.9 (.387)^2 = .74 m well above the height of the falls
There seems another way to do this
vy / vx = tan 43.2 vy = .939 vx
h = vy t - 1/2 g t^2 and t = 1.57 / vx
h = 1.57 tan 43.2 - 4.9 (1.57 / vx)^2
Solving for vx I get vx = 3.26 m/s vy = 3.06 m/s v = 4.47 m/s
The magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.
<h3>
Magnitude of required force to stop the weight</h3>
The magnitude of the force required to stop the weight in 0.333 seconds is calculated by applying Newton's second law of motion as shown below;
F = ma
F = m(v/t)
F = (mv)/t
F = (5 x 4.5)/0.333
F = 67.6 N
Thus, the magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.
Learn more about force here: brainly.com/question/12970081
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