What is the magnitude of the force that is exerted on a 20 kg mass to give it an acceleration of 10.0
1 answer:
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The range of the piece of paper is C) 1.4 m
Explanation:
The motion of the piece of paper is the motion of a projectile, which consists of two separate motions:
- A uniform motion along the horizontal direction, with constant velocity
- A uniformly accelerated motion along the vertical direction, with constant acceleration (the acceleration of gravity, )
From the equation of motion, it is possible to find an expression for the range (the total horizontal distance covered) of a projectile, which is given by:
where
u is the initial velocity
is the angle of projection
g is the acceleration of gravity
For the piece of paper in this problem,
u = 4.3 m/s
Substituting,
Learn more about projectile motion:
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Answer:
(a) r = 1.062·R =
(b) r =
(c) Zero
Explanation:
Here we have escape velocity v given by
and the maximum height given by
Therefore, when the initial speed is 0.241v we have
v = so that;
v² =
v² =
is then
Which gives
or
r = 1.062·R
(b) Here we have
Therefore we put in the maximum height equation to get
From which we get
r = 1.32·R
(c) The we have the least initial mechanical energy, ME given by
ME = KE - PE
Where the KE = PE required to leave the earth we have
ME = KE - KE = 0
The least initial mechanical energy to leave the earth is zero.