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4vir4ik [10]
3 years ago
13

In a coffee-cup calorimeter, 100.0 g of H2O and 100.0 mL of 1M HCl are mixed. The HCl had an initial temperature of 44.6 C and t

he water was originally at 24.6 C. After the reaction, the temperature of both substances is 31.3 C.
Required:
a. Was the reaction exothermic or endothermic? Explain.
b. Calculate how much heat the water lost or gained.
Chemistry
1 answer:
Hatshy [7]3 years ago
5 0

Answer:

Exothermic reaction for the HCl, endothermic reaction for the water

2803.28\ \text{J}

Explanation:

Heat was lost by HCl as its temperature lowered, so it was an exothermic reaction for the HCL.

Heat was gained by water as its temperature increased, so it was an endothermic reaction for the water.

m = Mass of water = 100 g

c = Specific heat of water = 4184\ \text{J/kg}^{\circ}\text{C}

\Delta T = Change in temperature of water = (31.3-24.6)^{\circ}\text{C}

Heat is given by

Q=mc\Delta T\\ =0.1\times 4184\times (31.3-24.6)\\ =2803.28\ \text{J}

Heat gained by water is 2803.28\ \text{J}.

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Answer:

The answer to your question is the mass of solute = 53.5 g

Explanation:

Data

mass of solution = 482 g

mass of solute = ?

mass percent = 11.1 %

Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution

Process

1.- Write the formula

        Mass percent = mass of solute / mass of solution x 100

-Solve for mass of solute

          mass of solute = Mass percent x mass of solution / 100

2.- Substitution

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3.- Simplification

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4.- Result

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Explanation:

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Answer:

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