Answer:

Explanation:
We are given the mass of two reactants, so this is a limiting reactant problem.
We know that we will need mases, moles, and molar masses, so, let's assemble all the data in one place, with molar masses above the formulas and masses below them.
M_r: 17.03 32.00 18.02
4NH₃ + 5O₂ ⟶ 4NO + 6H₂O
m/g: 70.1 70.1
Step 1. Calculate the moles of each reactant

Step 2. Identify the limiting reactant
Calculate the moles of H₂O we can obtain from each reactant.
From NH₃:
The molar ratio of H₂O:NH₃ is 6:4.

From O₂:
The molar ratio of H₂O:O₂ is 6:5.

O₂ is the limiting reactant because it gives the smaller amount of H₂O.
Step 3. Calculate the theoretical yield.

Answer:
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Explanation: what i just said
Answer:
Al(NO₃)₃ + (NH₄)₃PO₄ —> AlPO₄ + 3NH₄NO₃
The coefficients are: 1, 1, 1, 3
Explanation:
__Al(NO₃)₃ + __(NH₄)₃PO₄ —> __AlPO₄ + __NH₄NO₃
The above equation can be balance as illustrated below:
Al(NO₃)₃ + (NH₄)₃PO₄ —> AlPO₄ + NH₄NO₃
There are 12 atoms of H on the left side and 4 atoms on the right side. It can be balance by writing 3 before NH₄NO₃ as shown below:
Al(NO₃)₃ + (NH₄)₃PO₄ —> AlPO₄ + 3NH₄NO₃
Now the equation is balanced.
The coefficients are: 1, 1, 1, 3
Its<span> a nuclear process used for determining the concentrations of elements in a cast amount of materials.</span>
Answer:
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