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3 years ago

A solid substance is an excellent conductor of electricity. the chemical bonds in this substances are most likely

Chemistry

2 answers:

PSYCHO15rus [73]3 years ago

7 0

The answer is (4) metallic, because the valence electrons are mobile

marishachu [46]3 years ago

6 0

Answer;

-4. metallic, because the valance electrons are mobile

Explanation;

-Electrical conductivity in metals is a result of the movement of electrically charged particles.The atoms of metal elements are characterized by the presence of valence electrons (electrons in the outer shell of an atom) that are free to move about.

-Therefore; Metallic elements such as sodium and potassium conducts electricity in solid form due to the presence of delocalized valence electrons. These electrons can move freely within the structure of a metal when an electric current is applied.

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Is francium found in nature or lab?

ddd [48]

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It was the last element first discovered in nature, rather than by synthesis. Outside the laboratory, francium is extremely rare, with trace amounts found in uranium and thorium ores, where the isotope francium-223 continually forms and decays

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How much heat is required to increase the temperature of 198.5 grams of water from 25.0

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5.27*10^4 (52,700.)

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3 years ago

Which has a higher boiling point hcl or hi

Likurg_2 [28]

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-Payshence

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3. The exosphere is the outer layer of the

barxatty [35]

Answer:

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2 years ago

if the spin of one electron in an orbital is clockwise , what is the spin of the other electron in that orbital

nata0808 [166]

Here we have to get the spin of the other electron present in a orbital which already have an electron which has clockwise spin.

The electron will have anti-clockwise notation.

We know from the Pauli exclusion principle, no two electrons in an atom can have all the four quantum numbers i.e. principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m) and spin quantum number (s) same. The importance of the principle also restrict the possible number of electrons may be present in a particular orbital.

Let assume for an 1s orbital the possible values of four quantum numbers are n = 1, l = 0, m = 0 and s = $\frac{+}{-}$ $\frac{1}{2}$ .

The exclusion principle at once tells us that there may be only two unique sets of these quantum numbers:

1, 0, 0, + $\frac{1}{2}$ and 1, 0, 0, - $\frac{1}{2}$ .

Thus if one electron in an orbital has clockwise spin the other electron will must be have anti-clockwise spin.

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2 years ago