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lisabon 2012 [21]
3 years ago
7

A solid substance is an excellent conductor of electricity. the chemical bonds in this substances are most likely

Chemistry
2 answers:
PSYCHO15rus [73]3 years ago
7 0
The answer is (4) metallic, because the valence electrons are mobile
marishachu [46]3 years ago
6 0

Answer;

-4. metallic, because the valance electrons are mobile

Explanation;

-Electrical conductivity in metals is a result of the movement of electrically charged particles.The atoms of metal elements are characterized by the presence of valence electrons (electrons in the outer shell of an atom) that are free to move about.

-Therefore; Metallic elements such as sodium and potassium conducts electricity in solid form due to the presence of delocalized valence electrons. These electrons can move freely within the structure of a metal when an electric current is applied.

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Calculate the molarity of a solution if there are 1.5 mol of NaCl in 2.3 L of solution
frosja888 [35]

Answer:

0.6522 mol/L.

Explanation:

<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>

<em />

M = (no. of moles of solute)/(V of the solution (L)).

<em>∴ M = (no. of moles of solute)/(V of the solution (L)) </em>= (1.5 mol)/(2.3 L) = <em>0.6522 mol/L.</em>

7 0
3 years ago
Read 2 more answers
Is water wet? I give you a lot of points
UkoKoshka [18]

i mean technically, no. only because water is water and water makes things wet. you know? unless you pour water onto water then idk honestly, truly...

6 0
3 years ago
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The combustion of butane produces heat according to the equation 2C4H10(g) + 13O2(g) → 8CO2(g) + 10H2O(l), ΔH°rxn= –5,314 kJ/mol
Dafna11 [192]

Answer:

665 g

Explanation:

Let's consider the following thermochemical equation.

2 C₄H₁₀(g) + 13 O₂(g) → 8 CO₂(g) + 10 H₂O(l), ΔH°rxn= –5,314 kJ/mol

According to this equation, 5,314 kJ are released per 8 moles of CO₂. The moles produced when 1.00 × 10⁴ kJ are released are:

-1.00 × 10⁴ kJ × (8 mol CO₂/-5,314 kJ) = 15.1 mol CO₂

The molar mass of CO₂ is 44.01 g/mol. The mass corresponding to 15.1 moles is:

15.1 mol × 44.01 g/mol = 665 g

4 0
3 years ago
How many sulfur atoms are generated when 9.42 moles of H2S react according to the following equation: 2H2S+SO2→3S+2H2O
8_murik_8 [283]

Answer:

A) 8.51 × 10²⁴  

Explanation:

1. Gather all the information

            2H₂S + SO₂ ⟶ 3S + 2H₂O

n/mol:   9.42

2. Calculate the moles of S atoms

The molar ratio is 3 mol S:2 mol H₂S

\text{Moles of S} = \text{9.42 mol H$_{2}$S} \times \dfrac{\text{3 mol S }}{\text{2 mol H$_{2}$S }} = \text{14.13 mol S}

3. Calculate the atoms of S

\text{Atoms of S } = \text{14.13 mol S} \times \dfrac{6.022 \times 10^{23}\text{ S atoms}}{\text{1 mol S}} = \mathbf{8.51 \times 10^{24}}\textbf{ S atoms}

 

6 0
3 years ago
Read 2 more answers
Write a balanced chemical equation for the reaction between ammonium
Natasha2012 [34]

Answer:

 (NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→  AlPO₄(l) + 3NH₄NO₃(l)

Explanation:

Data Give:

Reaction between ammonium phosphate solution and solution of aluminum nitrate

  • Write a balanced chemical equation
  • include phase symbols

Details:

To write a balanced chemical equation we have to know formula units of compounds or molecules

Formula units

ammonium phosphate : (NH₄)₃PO₄

aluminum nitrate: Al(NO₃)₃

ammonium nitrate: NH₄NO₃

Now to write a chemical equation

  • we have to write the chemical formulas  or formula unit of each compound
  • write the reactant on left side of the arrow
  • write the product on the right side of the arrow
  • put a plus sign in 2 reactants and products on each side of the arrow
  • balance the equation by putting coefficient with compound formula
  • write the phase symbols on the right corner of the compound formula in brackets

So the Reaction will be

                      (NH₄)₃PO₄ + Al(NO₃)₃ -----------→  AlPO₄ + NH₄NO₃

Now balance the Chemical equation

                     (NH₄)₃PO₄ + Al(NO₃)₃ -----------→  AlPO₄ + 3NH₄NO₃

Now write the phase Symbols

                     (NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→  AlPO₄(l) + 3NH₄NO₃(l)

all compounds in the reaction are in liquid form and soluble in water

*** Note:

There is no aluminum nitrite in chemicals formulas

Also ammonium nitrite can not be used in pure isolated form due to its highly instability

4 0
3 years ago
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