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Alchen [17]
2 years ago
13

1) If you get paid $65.50 for 8.25 hours of work, what was your hourly pay? 1 point

Mathematics
1 answer:
Readme [11.4K]2 years ago
4 0

Answer:

7.94

Step-by-step explanation:

$65.50 ÷ 8.25 = 7.9393939394

7.9393939394 to the nearest hundredth is 7.94

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Find the slope to Y = 5/2x-3
son4ous [18]

Answer:

slope = 5/2

Step-by-step explanation:

This equation is written in slope intercept form

y = mx+b where m is the slope and b is the y intercept

y = 5/2x -3

The slope is 5/2 and the y intercept is -3

5 0
3 years ago
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Which of the following could be the function graphed?
Tpy6a [65]

Answer: The answer is (d)~f(x)=\dfrac{237x}{421x-515}.  


Step-by-step explanation: We are given four different functions of the variable 'x' and a graph. We are told to select one of the four options that which function can be graphed as the graph given in the question.

To check, we start plotting the functions one by one on a graph paper. We see that the graph of first three functions do not match with the given graph, but the graph of the fourth function given by

(d)~f(x)=\dfrac{237x}{421x-515}

matches exactly with the graph given in the question. The attached figure will show the graph for this function, which is exactly same as given.

Thus, the correct option is

(d)~f(x)=\dfrac{237x}{421x-515}


7 0
3 years ago
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Find quotient using long division
Nezavi [6.7K]

Answer:3x+5+(21)/x-4

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3 years ago
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ALGEBRA QUESTION PLS HELPS
cluponka [151]

The value of x is –7.

Solution:

Given expression:

$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}

Let us factor x^2+4x+3.

x^2+4x+3=(x+1)(x+3)

Substitute this in the fraction.

$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

To make the denominator same, multiply and divide the first term by (x +1).

$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

Denominators are same, you can add the fractions.

$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}

Cancel the common term in the numerator and denominator.

$\frac{x+7}{x+1} \cdot \frac{1}{x+1}

Multiply the fractions.

$\frac{x+7}{(x+1)^2}

$\frac{x+7}{x^2+2x+1}

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$\frac{x+7}{x^2+2x+1}=0

Do cross multiplication.

${x+7}=0\times (}{x^2+2x+1})

Any number or variable multiplied by 0 gives 0.

${x+7}=0

Subtract 7 from both sides of the equation.

${x+7-7}=0-7

x = –7

The value of x is –7.

7 0
2 years ago
PLEASE HELP ME I BEG YOU!?
weeeeeb [17]
The answer to question 5 is D.5 and the answer to question 9 is (-2,-6)
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3 years ago
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