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11111nata11111 [884]
3 years ago
14

the two ropes are used to vertically lower a 255 kg piano from exactly 4 m form a seocnd sotry window to the ground how much wor

k is done by each of the three forces
Physics
1 answer:
Ilya [14]3 years ago
6 0

Complete Question

The Question diagram is attached below

Answer:

a)  W_{Fg}= 12500 Nm

b)  W_{T_1}= - 6339.3Nm

c)  W_{T_2}= - 3662.8Nm

Explanation:

From the question we are told that:

Mass m=255kg

Distance d=4m

Generally the equation for Work done is mathematically given by

W=F*d

For F_g

W_{Fg}=2500 x 5.3

W_{Fg}= 12500 Nm

For T_1

W_{T_1}= - {1830 sin(60) x 4}

W_{T_1}= - 6339.3Nm

For T_2

W_{T_2}= - {1295  sin(45) x 4}

W_{T_2}= - 3662.8Nm

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Lera25 [3.4K]

Answer:

I would have to go with A, or maybe....yea A

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Juan measured the temperature of salt water. He then added 273 to the measured value. Which conversion is Juan most likely doing
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If Juan used a Celsius thermometer, it would tell him the Celsius temperature.

If he added 273 to that number, he'd have the "absolute" or Kelvin temperature.
7 0
3 years ago
The magnetic field in a solenoid is . A circular wire of radius 8 cm is concentric with a solenoid of radius 2 cm and length d =
defon

Answer:

6.03 mV

Explanation:

length of solenoid, L = 2 m, N = 12000, di/dt = 40 A/s,

Magnetic field due to solenoid

B = μ0 n i = μ0 N i / L

dB/dt = μ0 N / L x di / dt

dB /dt = (4 x 3.14 x 10^-7 x 12000 x 40) / 2 = 0.3 T/s

Induced emf, e = rate of change of magnetic flux

e = dΦ / dt = A x dB / dt

e = 3.14 x 0.08 x 0.08 x 0.3 = 6.03 x 10^-3 V = 6.03 mV

7 0
3 years ago
an electron is moving with a speed of 0.85c in a direction opposite to that of photon. calculate the relative velocity of the el
ololo11 [35]

Answer:

1.85c

Explanation:

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5 0
2 years ago
The noble gases neon (atomic mass 20.1797 u) and krypton (atomic mass 83.798 u) are accidentally mixed in a vessel that has a te
vagabundo [1.1K]

Answer:

(a) Kav Ne = Kav Kr = 7.29x10⁻²¹J

(b) v(rms) Ne= 659.6m/s and v(rms) Kr= 323.7m/s

Explanation:

(a) According to the kinetic theory of gases the average kinetic energy of the gases can be calculated by:

K_{av} = \frac{3}{2}kT (1)        

<em>where K_{av}: is the kinetic energy, k: Boltzmann constant = 1.38x10⁻²³J/K, and T: is the temperature </em>

<u>From equation (1), we can calculate the</u><u> average kinetic energies for the krypton and the neon:</u>

K_{av} = \frac{3}{2} (1.38\cdot 10^{-23} \frac{J}{K})(352.2K) = 7.29\cdot 10^{-21}J  

(b) The rms speeds of the gases can be calculated by:

K_{av} = \frac{1}{2}mv_{rms}^{2} \rightarrow v_{rms} = \sqrt \frac{2K_{av}}{m}  

<em>where m: is the mass of the gases and v_{rms}: is the root mean square speed of the gases</em>

For the neon:

v_{rms} = \sqrt \frac{2(7.29 \cdot 10^{-21}J)}{20.1797 \frac{g}{mol} \cdot \frac {1mol}{6.022\cdot 10^{23}molecules} \cdot \frac{1kg}{1000g}} = 659.6 \frac{m}{s}          

For the krypton:

v_{rms} = \sqrt \frac{2(7.29 \cdot 10^{-21}J)}{83.798 \frac{g}{mol} \cdot \frac {1mol}{6.022\cdot 10^{23}molecules} \cdot \frac{1kg}{1000g}} = 323.7 \frac{m}{s}  

Have a nice day!

3 0
3 years ago
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