Answer:
<h2>6000 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 300 × 20
We have the final answer as
<h3>6000 J</h3>
Hope this helps you
The force applied on the fly and the windshield are equal based on Newton's Law of Action and Reaction. the difference between them is that the fly's body does not have enough mechanical strength to withstand the force but the windshield does.
Answer:
The distance is 2 cm
Solution:
According to the question:
Magnetic field of Earth, B_{E} = ![5.0\times 10^{- 5} T](https://tex.z-dn.net/?f=5.0%5Ctimes%2010%5E%7B-%205%7D%20T)
Current, I = 5.0 A
We know that the formula of magnetic field is given by:
![B = \farc{\mu_{o}I}{2\pi d}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfarc%7B%5Cmu_%7Bo%7DI%7D%7B2%5Cpi%20d%7D)
where
d = distance from current carrying wire
Now,
![d = \frac{\mu_{o}I}{2\pi B}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B%5Cmu_%7Bo%7DI%7D%7B2%5Cpi%20B%7D)
![d = \frac{4\pi\times 10^{- 7}\times 5.0}{2\pi\times 5.0\times 10^{- 5}}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B4%5Cpi%5Ctimes%2010%5E%7B-%207%7D%5Ctimes%205.0%7D%7B2%5Cpi%5Ctimes%205.0%5Ctimes%2010%5E%7B-%205%7D%7D)
d = 0.02 m 2 cm
Answer:
The angle of the launch is 17.09 degrees.
Explanation:
Given that,
The initial speed of a cannon is 100 m/s
It is launched at some angle and it lands after being in the air for 6 s.
We need to find the angle of the launch.
The time taken by the projectile to reach the ground is called the time of flight. It is given by the formula as follows :
![T=\dfrac{2u\sin\theta}{g}](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7B2u%5Csin%5Ctheta%7D%7Bg%7D)
Here,
= launch angle
![\sin\theta=\dfrac{Tg}{2u}\\\\\sin\theta=\dfrac{6\times 9.8}{2\times 100}\\\\\theta=\sin^{-1}(0.294)\\\\\theta=17.09^{\circ}](https://tex.z-dn.net/?f=%5Csin%5Ctheta%3D%5Cdfrac%7BTg%7D%7B2u%7D%5C%5C%5C%5C%5Csin%5Ctheta%3D%5Cdfrac%7B6%5Ctimes%209.8%7D%7B2%5Ctimes%20100%7D%5C%5C%5C%5C%5Ctheta%3D%5Csin%5E%7B-1%7D%280.294%29%5C%5C%5C%5C%5Ctheta%3D17.09%5E%7B%5Ccirc%7D)
Hence, the angle of the launch is 17.09 degrees.
Answer:
1÷60 h
time equals distance upon speed