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serg [7]
3 years ago
10

What is net force

Physics
1 answer:
IgorLugansk [536]3 years ago
3 0
The answer is letter A
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21. If the Sun's rays were at 45° to a vertical pillar, how would
diamong [38]

Answer:

Let the height of the pole AB = x m. ∴ Length of shadow OB ol the pole AB = x m. Let the angle of elevation be ө, i.e. Hence, the angle of elevation of the Sun's altitude is 45°.

Explanation:

4 0
3 years ago
A roller coaster car of mass m = 300 kg is released from rest at the top of a 60 m high hill (position A), and rolls with a negl
Triss [41]

Answer:

The principle of conservation of energy and angular momentum

Explanation:

At point A, the car experienced maximum of potential energy

As it moves down the hill, the potential energy decreases while the kinetic energy increases.

The maximum kinetic energy of the car is needed for the attainment of enough centripetal force to help the car move through the loop without falling .

7 0
2 years ago
PLEASE HELP ASAP!!!<br> GIVING BRAINLIEST!!!<br> 40 points!!
Nana76 [90]
W = Fd = 4(2100) = 8400 J

So the answer is A) 8400 J


I was just rewriting my notes on the work lesson I did in class today, so I saw this question at the perfect time!! :)

Hope it helps!! :)
4 0
3 years ago
Read 2 more answers
An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.40 kW. A receiving antenna 6
lara [203]

To solve the problem we will apply the concepts related to the Intensity as a function of the power and the area, as well as the electric field as a function of the current, the speed of light and the permeability in free space, as shown below.

The intensity of the wave at the receiver is

I = \frac{P_{avg}}{A}

I = \frac{P_{avg}}{4\pi r^2}

I = \frac{3.4*10^3}{4\pi(4*1609.34)^2} \rightarrow 1mile = 1609.3m

I = 6.529*10^{-6}W/m^2

The amplitude of electric field at the receiver is

I = \frac{E_{max}^2}{2\mu_0 c}

E_{max}= \sqrt{2I\mu_0 c}

The amplitude of induced emf by this signal between the ends of the receiving antenna is

\epsilon_{max} = E_{max} d

\epsilon_{max} = \sqrt{2I \mu_0 cd}

Here,

I = Current

\mu_0 = Permeability at free space

c = Light speed

d = Distance

Replacing,

\epsilon_{max} = \sqrt{2(6.529*10^{-6})(4\pi*10^{-7})(3*10^{8})(60.0*10^{-2})}

\epsilon_{max} = 0.05434V

Thus, the amplitude of induced emf by this signal between the ends of the receiving antenna is 0.0543V

6 0
3 years ago
How much power is used if a force of 54 newtons is used to pull a wagon a distance of 10 meters in 6 seconds?
AnnZ [28]
First, calculate the work done: 54 x 10 = 540J.
Now calculate power: 540 / 6 = 90.
The answer is 90W.

Hope this helps.
7 0
3 years ago
Read 2 more answers
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