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mihalych1998 [28]
3 years ago
13

Cody's family went hiking along a stream in Georgia and found a waterfall. At the bottom of the waterfall, they noticed many sma

ll pebbles with smooth edges on the bottom of the stream. If Cody's family added more rocks to the stream at the bottom of the waterfall, what should they expect to happen to the size of the rocks?
Physics
1 answer:
Vitek1552 [10]3 years ago
4 0

Answer:

They can expect the size of the rocks to get smaller as the time passes.

Explanation:

They can expect the size of the rocks to get smaller as the time passes.

  • This is so because the water falling from certain height under waterfall will exert mechanical impact on the rock due to the mass of the water. This will act as water hammer <em>causing wear and tear</em> to the rock particles and flowing them away with the stream of water.
  • This hydraulic shock is generated when there is sudden stoppage in the motion of water. In sync with Newton's second law of motion, when the momentum of water is changed within a short course of time it creates a hammer like impact which has potential  of wear and tear when an object is continuously subjected to it.
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Hey! anybody knows the answer then help me i will mark your answer!!!
Volgvan

10/9

Explanation:

option 2 is the correct answer

8 0
2 years ago
A 4.00 kg ball is swung in a circle on the edge of a 1.50 m rope. The time it takes for the ball to complete one rotation is 3.4
lorasvet [3.4K]

Answer:

The answer is below

Explanation:

The length of the rope is equal to the radius of the circle formed by the complete rotation of the rope. Therefore the radius = 1.50 m.

a) The distance covered by the rope when completing one rotation is the same as the perimeter of the circle. Hence:

Distance covered in one rotation = 2π * radius = 2π * 1.5 = 3π meters

The velocity of the ball = Distance / time = 3π meters / 3.4 seconds = 2.77  m/s

b) The initial velocity (u) is 0 m/s, the final velocity is 2.77 m/s during time (t) = 3.4 s. Hence acceleration (a):

v = u + at

2.77 = 3.4a

a = 0.82 m/s²

c) Force on ball = mass * acceleration = 4 * 0.82 = 3.28 N

8 0
2 years ago
How does a real image differ from a virtual image?
Snezhnost [94]

Answer:

one contains datta that can take up hard drive or disc space weras a picture takes up space on walls or photo albums

Explanation:

6 0
2 years ago
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What best describes the volcanic process of magma with dissolved water vapor and other gases as it nears the Earth surface?
Assoli18 [71]

Answer:

Pressure on the molten rock lessens and the gases dissolved in rock can bubble and expand rapidly causing violent eruptions.

Explanation:

that's just how it works lol. hope this helps :]

6 0
2 years ago
A Ferris wheel turns at a constant 150.0 revolutions per hour. (a) Express this rate of rotation in units of radians per second.
RUDIKE [14]

Answer:

(a) 0.261 rad/s

(b) 1007.72 m

Explanation:

The angular velocity of the Ferris wheel is 150.0 revolutions per hour.

(a) To calculate the angular velocity of the wheel in units of radians per second, you take into account the following equivalence:

1 hour = 3600 seconds

1 revolution = 2π radians

You use the previous conversion factors:

150.0\ \frac{rev}{h}*\frac{2\pi \ rad}{1\ rev}*\frac{1\ h}{3600\ s}=0.261\frac{rad}{s}

In units of radians per seconds the wheel turns at 0.261 rad/s

(b) To find the arc length described by the wheel, you first calculate the angle described by the  wheel in the time t, by using the following formula:

\theta=\omega t     (1)

ω: angular velocity = 0.261 rad/s

t: time = 4.95 min

You first convert the time to units of seconds

4.95min*\frac{60s}{1min}=297s

Next, you replace the values of the parameters in the equation (1):

\theta=(0.261\frac{rad}{s})(297s)=77.51rad

Next, you use the following formula for the arc length:

s=r\theta     (2)

r: radius of the wheel = 13.0 m

You replace the values of the parameters in the equation (2):

s=(13.0m)(77.51rad)=1007.72m

The arc length described by the wheel is 1007.72m

4 0
3 years ago
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