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PtichkaEL [24]
3 years ago
5

______ involves the use of electronic equipment to verify that an offender is at home or in a community correctional center duri

ng specified hours or to track his or her whereabouts.
Physics
1 answer:
erastova [34]3 years ago
3 0

Answer:

Remote Location Monitoring

Explanation:

Remote Location Monitoring involves the use of electronic equipment to verify that an offender is at home or in a community correctional center during specified hours o to track his her whereabouts.

Using programmed contact to verify an offenders location that distant, varied by the use of Global positioning system (GPS) to continuously map the exact location of the offender.

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Tire inflation is very important to the safe and economical operation of any vehicle. Technician A says that the tire pressure s
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Answer:

Both technicians A and B are correct, the information on how to fill the car tires can be located on the tire and on the placard on the driver's door jam

Explanation:

The instruction on proper inflation of car tires can be found on the tire information placard in the door jam area or the fuel filler door, in the glove box or in the car or tire manual

The tire information of the proper pressure to fill the tires is also visibly engraved on the sides of the car tire, where other information such as the requirement for training on tire filling/changing, safety precautions and manufacturer's information

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4 years ago
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1:
Deffense [45]

Explanation:

the car will be brought back

7 0
3 years ago
Fill in the physical properties of oxygen cited in the text: color: solubility in water: freezing point: ?c boiling point: ?c
dexar [7]

Colour: Colourless

Solubility in water: Slight

Freezing point: -218

I didn't get the boiling point

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3 years ago
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Two bodies, with heat capacitiesC1andC2(assumed independent oftemperature) and initial temperatureT1andT2, respectively, are pla
Anna007 [38]

Answer:

Tբ = (C₁T₁ + C₂T₂)/(C₁ + C₂) = (C₁T₁)/(C₁ + C₂) + (C₂T₂)/(C₁ + C₂)

Explanation:

Let's Assume that T₁ > T₂, this means that, T₁ > Tբ > T₂

The zeroth law of thermodynamics explains that two bodies in thermal equilibrium will eventually end up with the same final body temperature.

Heat lost by body 1 = Heat gained by body 2

C₁ (T₁ - Tբ) = C₂ (Tբ - T₂)

C₁T₁ - C₁Tբ = C₂Tբ - C₂T₂

C₁Tբ + C₂Tբ = C₁T₁ + C₂T₂

Tբ(C₁ + C₂) = C₁T₁ + C₂T₂

Tբ = (C₁T₁ + C₂T₂)/(C₁ + C₂)

Tբ = (C₁T₁)/(C₁ + C₂) + (C₂T₂)/(C₁ + C₂)

4 0
3 years ago
Suppose a rocket ship accelerates upwards with acceleration equal in magnitude to twice the magnitude of g (we say that the rock
pashok25 [27]

Answer:

a) s_a=98100\ m is the height where the rocket stops accelerating and its fuel is finished and starts decelerating while it still continues to move in the upward direction.

b) v_a=1962\ m.s^{-1} is speed of the rocket going when it stops accelerating.

c) H=294300\ m

d) t_T=544.95\ s

e) Zero, since the average velocity is the net displacement per unit time and when the rocket strikes back the earth surface the net displacement is zero.

Explanation:

Given:

acceleration of rocket, a=2g=2\times 9.81=19.62\ m.s^{-2}

time for which the rocket accelerates, t_a=100\ s

<u>For the course of upward acceleration:</u>

using eq. of motion,

s_a=ut+\frac{1}{2}at_a^2

where:

u= initial velocity of the rocket at the launch =0

s_a= height the rocket travels just before its fuel finishes off

so,

s_a=0+\frac{1}{2}\times 19.62\times 100^2

a) s_a=98100\ m is the height where the rocket stops accelerating and its fuel is finished and starts decelerating while it still continues to move in the upward direction.

<u>Now the velocity of the rocket just after the fuel is finished:</u>

v_a=u+at_a

v_a=0+19.62\times 100

b) v_a=1962\ m.s^{-1} is speed of the rocket going when it stops accelerating.

After the fuel is finished the rocket starts to decelerates. So, we find the height of the rocket before it begins to fall back towards the earth.

Now the additional height the rocket ascends before it begins to fall back on the earth after the fuel is consumed completely, at this point its instantaneous velocity is zero:

using equation of motion,

v^2=v_a^2-2gh

where:

g= acceleration due to gravity

v= final velocity of the rocket at the top height

0^2=1962^2-2\times 9.81\times h

h=196200\ m

c) So the total height at which the rocket gets:

H=h+s

H=196200+98100

H=294300\ m

d)

Time taken by the rocket to reach the top height after the fuel is over:

v=v_a+g.t

0=1962-9.81t

t=200\ s

Now the time taken to fall from the total height:

H=v.t'+\frac{1}{2}\times gt'^2

294300=0+0.5\times 9.81\times t'^2

t'=244.95\ s

Hence the total time taken by the rocket to strike back on the earth:

t_T=t_a+t+t'

t_T=100+200+244.95

t_T=544.95\ s

e)

Zero, since the average velocity is the net displacement per unit time and when the rocket strikes back the earth surface the net displacement is zero.

8 0
3 years ago
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