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gayaneshka [121]
3 years ago
5

Question above! Science 8 please help!

Physics
2 answers:
Darina [25.2K]3 years ago
6 0
Answer A) the watermelon has more inertia so it takes more force to move it.
Kamila [148]3 years ago
5 0

Answer:

A. the watermeleon has more inertia

Explanation:

the heavier the mass of an object is, the more force it takes to move it.

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Why malleability is a useful property
Rom4ik [11]
Malleability is a useful property because it allows many products to be made in manufacturing.
4 0
3 years ago
Why does a crumpled paper land before a flat sheet of paper?
Nitella [24]

Answer:

The crumpled paper hits the ground first due to air resistance. The crumpled paper has less surface area than the flat paper, therefore the crumpled paper hits first.

I hope this helped. If you could mark brainliest that would be greatly appreciated.

8 0
3 years ago
Read 2 more answers
B. The coefficient of friction between the tires and the road is 0.850 and the mass of the car is
Mrac [35]

Answer:

156.26N

Explanation:

The data needed are incomplete. Let the acceleration of the body be 3.5m/s²

Other given parameters

Mass = 1.35×10^1 = 13.5kg

coefficient of friction between the tires and the road = 0.850

Acceleration due to gravity = 9.8m/s²

According to Newton's second law:

Fnet = ma

Fnet = Fapp - Ff

Fapp is the applied force

Ff is the frictional force = umg

The equation becomes:

Fapp - Ff = ma

Fapp-umg = ma

Fapp - 0.85(13.5)(9.8) = 13.5(3.5)

Fapp - 109.0125 = 47.25

Fapp = 47.25+109.0125

Fapp = 156.2625N

Hence the applied force that caused the acceleration is 156.26N

Note that the acceleration of the car was assumed. Any value of acceleration can be used for the calculation.

8 0
3 years ago
Block 1 of mass m1 slides along a frictionless floor and into a one-dimensional elastic collision with stationary block 2 of mas
Elan Coil [88]
<span>Answers: (a) 2.0 m/s (b) 4 m/s

Method:

(a) By conservation of momentum, the velocity of the center of mass is unchanged, i.e., 2.0 m/s.

(b) The velocity of the center of mass = (m1v1+m2v2) / (m1+m2)

Since the second mass is initially at rest, vcom = m1v1 / (m1+m2)

Therefore, the initial v1 = vcom (m1+m2) / m1 = 2.0 m/s x 6 = 12 m/s

Since the second mass is initially at rest, v2f = v1i (2m1 /m1+m2 ) = 12 m/s (2/6) = 4 m/s </span>
7 0
3 years ago
By what factor does the force required to stop a car increase if the initial speed is doubled and the stopping distance remains
mojhsa [17]
 <span>Since the equation is F = ma the acceleration would change by a factor of 2, since a = v/2. The force would double.</span>
4 0
4 years ago
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