All categories

3 years ago

Friction is just hot air rubbing off the inevitable force of solid prove me wrong

Physics

1 answer:

Lorico [155]3 years ago

3 0

Answer:

friction is when two objects tough with force basically. when an object is rubbed against something. when an object comes in contact with something else. or ig u can call it hot air rubbing off the inevitable force lol that works too , bud

whatever helps u rememeber

You might be interested in

Fill out the blanks, this is for science!

dusya [7]

Faster and higher I believe.

8 0

3 years ago

Read 2 more answers

UGH PLSSSS HELP WILL GIVE BRAINLIEST, AND 20 POINTS

Svetradugi [14.3K]

Answer:

false

Explanation:

the answer is false bc for a non-polar bond to form the electrons are shared equally...

7 0

3 years ago

One of the harmonics on a string 1.30m long has a frequency of 15.60 Hz. The next higher harmonic has a frequency of 23.40 Hz. F

Alja [10]

Answer:

$\large \boxed{\text{(a) 7.800 Hz; (b) 20.3 m/s; 40.6 m/s; 60.8 m/s}}$

Explanation:

a) Fundamental frequency

A harmonic is an integral multiple of the fundamental frequency.

$\dfrac{\text{23.40 Hz}}{\text{15.60 Hz}} = \dfrac{1.500}{1} \approx \dfrac{3}{2}$

$f = \dfrac{\text{24.30 Hz}}{3} = \textbf{7.800 Hz}$

b) Wave speed

(i) Calculate the wavelength

In a fundamental vibration, the length of the string is half the wavelength.

$\begin{array}{rcl}L & = & \dfrac{\lambda}{2}\\\\\text{1.30 m} & = & \dfrac{\lambda}{2}\\\\\lambda & = & \text{2.60 m}\\\end{array}$

(b) Calculate the speed s

$\begin{array}{rcl}v_{1}& = & f_{1}\lambda\\& = & \text{7.800 s}^{-1} \times \text{2.60 m}\\& = & \textbf{20.3 m/s}\\\end{array}$

$\begin{array}{rcl}v_{2}& = & f_{2}\lambda\\& = & \text{15.60 s}^{-1} \times \text{2.60 m}\\& = & \textbf{40.6 m/s}\\\end{array}$

$\begin{array}{rcl}v_{3}& = & f_{3}\lambda\\& = & \text{23.40 s}^{-1} \times \text{2.60 m}\\& = & \textbf{60.8 m/s}\\\end{array}$

4 0

3 years ago

How does adding more of a substance affect it's density?

fomenos

I’m going to use molasses as an example of a substance.

The mass and volume both change when changing the amount of molasses.
However, the density does not change. This is because the mass and volume increase at the same rate/proportion!

Even though there is more molasses (mass) in test tube A, the molasses also takes up more space (volume). Therefore, the spacing between those tiny particles that make up the molasses is constant (does not change).

The size or amount of a material/substance does not affect its density.

5 0

3 years ago

Read 2 more answers

Select the correct statement to describe when a sample of liquid water vaporizes into water vapor. Question 12 options: Temperat

pashok25 [27]

<span>temperature increases and molecular motion increases while shape becomes less defined.

</span>

3 0

3 years ago