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Fiesta28 [93]
3 years ago
11

Please fill in the blanks:

Chemistry
1 answer:
marysya [2.9K]3 years ago
8 0

Answer:

1 large

2 small

balance out means remove

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14.2 grams of Na2SO4 is dissolved in water to make a 2.50 L
Trava [24]

Answer:

0.04 M

Explanation:

Given data:

Mass of Na₂SO₄= 14.2 g

Volume of solution = 2.50 L

Molarity of solution = ?

Solution:

Number of moles of Na₂SO₄:

Number of moles = mass/ molar mass

Number of moles = 14.2 g/ 142.04 g/mol

Number of moles = 0.1 mol

Molarity :

Molarity = number of moles of solute / volume of solution in L

Molarity = 0.1 mol / 2.50 L

Molarity = 0.04 M

6 0
3 years ago
What are the benefits and limitations to relative dating rock layer?
vlabodo [156]
Relative dating can only determine the sequential order<span> of events, not the exact date which something occurred. It is useful for being able to determine a timeline of events in an exact point, but won't give a full picture of events in the past nor account for the age of material. 

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4 0
3 years ago
In an experiment, a student needs 250.0 mL of a 0.100 M copper (II) chloride solution. A stock solution of 2.00 M copper (II) ch
LekaFEV [45]

Answer : The volume of stock solution needed are, 12.5 mL

Explanation :

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of copper (II) chloride.

M_2\text{ and }V_2 are the final molarity and volume of stock solution of copper (II) chloride.

We are given:

M_1=0.100M\\V_1=250.0mL\\M_2=2.00M\\V_2=?

Putting values in above equation, we get:

0.100M\times 250.0mL=2.00M\times V_2\\\\V_2=12.5mL

Hence, the volume of stock solution needed are, 12.5 mL

8 0
3 years ago
Determine how many gmol, kmol, and lbmols there are in 50 kilograms of n-hexane.
Artist 52 [7]

Answer: 581 gmol

0.581 kmol

1.28\times 10^{-3}lbmol

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{50\times 1000g}{86g/mol}=581mol

1. The conversion for mol to gmol

1 mol = 1 gmol

581 mol= \frac{1}{1}\times 581=581gmol

2. The conversion for mol to kmol

1 mol = 0.001 kmol

581 mol= \frac{0.001}{1}\times 581=0.581kmol

3. The conversion for mol to lbmol

1 mol = 2.2\times 10^{-3}lbmol

581 mol= \frac{2.2\times 10^{-3}}{1}\times 581=1.28\times 10^{-3}lbmol

3 0
3 years ago
so they are asking me to find the empirical formula for a compound that is 7.70% carbon and 92.3% chlorine. Can you show me step
Nikolay [14]

Answer:

Empirical formula is CCl₄

Explanation:

Given data:

Percentage of carbon = 7.70%

Percentage of chlorine = 92.3%

Empirical formula = ?

Solution:

Number of gram atoms of Cl = 92.3 / 35.5 = 2.6

Number of gram atoms of C = 7.70 / 12 = 0.64

Atomic ratio:

            C                      :              Cl            

           0.64/0.64        :             2.6/0.64

            1                      :                4        

C : Cl  = 1 : 4

Empirical formula is CCl₄.

5 0
3 years ago
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