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Fiesta28 [93]
3 years ago
11

Please fill in the blanks:

Chemistry
1 answer:
marysya [2.9K]3 years ago
8 0

Answer:

1 large

2 small

balance out means remove

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Rank the metals from most reactive (1) to least reactive (3) silver, strontium, and technetium
Natasha2012 [34]

Answer:

1 = strontium

2 = technetium

3 = silver

Explanation:

Strontium is present in 2 group of periodic table. It is alkaline earth metal. It is most reactive element and can not found free in nature. it  is insoluble in water but react with water and form strontium hydroxide and hydrogen gas is also produced. It is radioactive element.

It is similar to the calcium and can incorporated into bones. The food rich with strontium is used to avoid the osteoporosis. It is found in leafy vegetables, grains, sea foods etc.

In given series strontium is highest in reactivity then technetium, while the technetium is more reactive than silver. The silver is less reactive as compared to both given elements.

7 0
3 years ago
Read 2 more answers
Please helpp <br> A B C or D <br> ???
Korvikt [17]

Answer:

C

Explanation:

Lime water turns cloudy when it reacts Carbon dioxide

5 0
3 years ago
Read 2 more answers
Which mass of urea CO(NH2)2 contain the same mass of nitrogen as 101.1g of potassium nitrate?
Sliva [168]
M(KNO₃)=101.1 g/mol
M(CO(NH₂)₂)=60.1 g/mol

m(N)=M(N)m(KNO₃)/M(KNO₃)

m(N)=2M(N)m(CO(NH₂)₂)/M(CO(NH₂)₂)

2m(CO(NH₂)₂)/M(CO(NH₂)₂)=m(KNO₃)/M(KNO₃)

m(CO(NH₂)₂)=M(CO(NH₂)₂)m(KNO₃)/(2M(KNO₃))

m(CO(NH₂)₂)=60.1*101.1/(2*101.1)=30.05 g
7 0
4 years ago
The voltage for the following cell is +0.731 V. Find Kb for the organic base RNH2. Use EscE 0.241V.
tino4ka555 [31]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The  value is   K_b  =   1.89 *10^{-6}

Explanation:

From the question we are told that

   The  voltage of the cell is  V  =  0.731 \  V

Generally K_b is mathematically represented as  

           K_b  =  \frac{K_w }{ K_a }

Where  K_w  is the equilibrium constant for this auto-ionization of water with a value  K_w  =  1.0 *10^{-14}

Generally the E_{cell} is mathematically represented as

       E_{cell} =  V  -  E_{SCE}

=>     E_{cell} =  0.731 - 0.241

=>       E_{cell} =   0.49 V

This  E_{cell} is mathematically represented as

             E_{cell} =  \frac{0.0592}{n} *  log K_a

Where n is the number of moles which in this question is  n = 1

         So  

         0.490 =  \frac{0.0592}{1}  *  log K_a

=>      K_a  =  5.30*10^{-9}

So  

     K_b  =  \frac{ K_w}{ K_a}

=>   K_b  =  \frac{1.0 *10^{-14}}{ 5.30*10^{-9}}

=>    K_b  =   1.89 *10^{-6}

5 0
3 years ago
How many moles are there in 45.6 grams of yttrium?
leva [86]
Number of moles = mass/ molar mass
= 45.6g / 88.90g/mol
= 0.512 moles
4 0
3 years ago
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