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horsena [70]
3 years ago
13

2134211-12431-24143x=1312431

Physics
1 answer:
kondor19780726 [428]3 years ago
4 0

Answer:

33.5

Explanation:

The given expression is;

          2134211  - 12431  - 24143x  = 1312431

To solve this problem, simplify the similar terms;

          2121780 - 24143x  = 1312431

                  - 24143x  = 1312431 - 2121780

                   - 24143x  = -809349

     divide both sides of the expression by -24143;

                      x  = 33.5

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In the simplified version of Kepler's third law, P 2 = a3, the units of the orbital period P and the semimajor axis a of the ell
Orlov [11]

Answer:

The units of the orbital period P is <em>years </em> and the units of the semimajor axis a is <em>astronomical units</em>.

Explanation:

P² = a³ is the simplified version of Kepler's third law which governs the orbital motion of large bodies that orbit around a star. The orbit of each planet is an ellipse with the star at the focal point.

Therefore, if you square the year of each planet and divide it by the distance that it is from the star, you will get the same number for all the other planets.

Thus, the units of the orbital period P is <em>years </em> and the units of the semimajor axis a is <em>astronomical units</em>.

8 0
3 years ago
An object moves on a trajectory given by Bold r left parenthesis t right parenthesis equals left angle 10 cosine 6 t comma 10 si
spayn [35]

Answer:

10

Explanation:

(r) = <10 cos 6t, 10 Sin 6t>

The distance traveled by the object is the magnitude of vector r.

The magnitude of vector r is given by

r = \sqrt{(10 Cos 6t)^{2}+(10 Sin 6t)^{2}}

r =10 \sqrt{(Cos^{2} 6t)+(Sin^{2} 6t)

r = 10        

5 0
3 years ago
How much work in joules must be done to stop a 920-kg car traveling at 90 km/h?
tankabanditka [31]

Answer:

Work done, W = −287500 Joules

Explanation:

It is given that,

Mass of the car, m = 920 kg

The car is travelling at a speed of, u = 90 km/h = 25 m/s

We need to find the amount of work must be done to stop this car. The final velocity of the car, v = 0

Work done is also defined as the change in kinetic energy of an object i.e.

W=\Delta K

W=\dfrac{1}{2}m(v^2-u^2)

W=\dfrac{1}{2}\times 920\ kg(0-(25\ m/s)^2)

W = −287500 Joules

Negative sign shows the work done is done is opposite direction.

3 0
3 years ago
15. To use your left hand to determine the direction of the voltage developed in a moving conductor in a stationary magnetic fie
alukav5142 [94]
<span>"forefinger in the direction of the lines of force" 100% correct, I took the test.</span>
8 0
4 years ago
Read 2 more answers
A rectangular loop of wire with dimensions 1.80 cm by 9.00 cm and resistance 0.800 Ω is being pulled to the right out of a regio
sladkih [1.3K]

(a) The magnitude of the force that the magnetic field exerts on the loop is 0.042 N.

(b) The direction of the force that the magnetic field exerts on the loop will be out of the plane.

<h3>Magnetic force exerted on the loop</h3>

F = BIL

where;

  • I is current in the loop
  • L is length of the loop

emf = BVb

where;

  • b is breadth of the loop
  • V is velocity
  • B is magnetic field

emf = 2.6 x 3 x 0.018 = 0.1404 V

Current in the loop, I = emf/R = 0.1404/0.8 = 0.18 A

<h3>Magnetic force</h3>

F = BIL

where;

  • L is length of the loop

F = 2.6 x 0.18 x 0.09 = 0.042 N

<h3>Direction of the force</h3>

The direction of the force that the magnetic field exerts on the loop will be out of the plane.

Learn more about magnetic force here: brainly.com/question/13277365

#SPJ1

7 0
2 years ago
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