Answer:
Explanation:
In this case we shall calculate rate of change of flux in the coli to calculate induced emf .
Flux through the coil = no of turns x area x magnetic field perpendicular to it
=34 x 2.25 x (3.95 )²x 10⁻⁴ Weber
= 1193.4 x 10⁻⁴Weber
Final flux through the coil after turn by 90°
= 1193.4 x 10⁻⁴ cos 90 ° =0
Change of flux
= 1193.4 x 10⁻⁴ weber.
Time taken = 0.335 s .
Average emf= Rate of change of flux
= change in flux / time
=1193.4 x 10⁻⁴ / .335
= 3562.4 x 10⁻⁴
356.24 x 10⁻³
=356.24 mV.
Current induced = emf induced / resistance
= 356.24/.780
= 456.71 mA.
Answer:
1.11 s.
Explanation:
From the question given above, the following data were obtained:
Height (H) = 6 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =.?
The time taken for the branch to hit the ground can be obtained as follow:
H = ½gt²
6 = ½ × 9.8 × t²
6 = 4.9 × t²
Divide both side by 4.9
t² = 6/4.9
Take the square root of both side
t = √(6/4.9)
t = 1.11 s
Therefore, it will take 1.11 s for the branch to hit the ground.
<span>The flywheel is solid cylindrical disc. Moment of inertial = ½ * mass * radius^2
Mass = 40.0 kg
Radius = ½ * 76.0 cm = 38 cm = 0.38 meter
Moment of inertial = ½ * 41 * 0.36^2
Convert rpm to radians/second
The distance of 1 revolution = 1 circumference = 2 * π * r
The number of radians/s in 1 revolution = 2 * π
1 minute = 60 seconds
1 revolution per minute = 2 * π radians / 60 seconds = π/30 rad/s
Initial angular velocity = 500 * π/30 = 16.667 * π rad/s
170 revolutions = 170 * 2 * π = 340 * π radians
The flywheel’s initial angular velocity = 16.667 * π rad/s. It decelerated at the rate of 1.071 rad/s^2 for 48.89 seconds.
θ = ωi * t + ½ * α * t^2
θ = 16.667 * π * 48.89 + ½ * -1.071 * 48.89^2
2559.9 - 1280
θ = 1280 radians</span>
Answer:
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The question involves the knowledge of kinematics and dynamics. The answers are;
a) Time taken to stop the car = 10 s
b) The operation that slows the car is Friction
c) The size of the force = 1200 N
<h3>
What is Deceleration ?</h3>
Deceleration is the opposite of acceleration. When an object is going to rest, it will be decelerating and the final velocity will be equal to zero.
Given that the driver of a car moving at 15 m/s along a straight level road applies the brakes. The car decelerates at a steady rate of 3/2 m/s²
a) How long does the car take to stop can be found by using the formula
v = u - at
Where
Substitute all the parameters into the formula
0 = 15 - 1.5t
1.5t = 15
t = 15/1.5
t = 10 s
b) The description of the operation that slows the car down after the brake pedal is pressed is simply friction.
c) If the mass of the car is 800. The size of the force slowing the car down will be F = ma
F = 800 × 1.5
F = 1200 N
Therefore, the time taken to stop the car is 10 s and the force slowing the car down is 1200 N
Learn more about Acceleration here: brainly.com/question/605631
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