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laiz [17]
3 years ago
6

Resuelva el siguiente ejercicio. Un armario de 120 kg descansa sobre una superficie plana, determine la fuerza de rozamiento si

el coeficiente de rozamiento para el cuerpo vale 0,4 y realice un gráfico indicando las fuerzas indicando las fuerzas que actúan el en armario.
Physics
1 answer:
aalyn [17]3 years ago
4 0

Responder:

470.4N

Explicación:

La fuerza de fricción se expresa mediante la fórmula;

Ff = nR

n es el coeficiente de fricción

R es la reacción

R = peso = mg

Ff = nmg

Dado

n = 0,4

masa m = 120kg

g es la aceleración debida a la gravedad = 9,8 m / s²

Sustituir en la fórmula;

Ff = 0,4 (120) (9,8)

Ff = 470,4 N

Por tanto, la fuerza de fricción es 470,4 N

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Answer:

Correct answer:  E total = 2,800 J

Explanation:

Given:

m = 4 kg   the mass of the object

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E total = ? J

The total energy of an object is equal to the sum of potential and kinetic energy

E total = Ep + Ek

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Ep = 4 · 10 · 50 = 2,000 J

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Ek = 4 · 20² / 2 = 2 · 400 = 800 J

E total = 2,000 + 800 = 2,800 J

E total = 2,800 J

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Answer:

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Explanation:

We are given that

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