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2 years ago

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Resuelva el siguiente ejercicio. Un armario de 120 kg descansa sobre una superficie plana, determine la fuerza de rozamiento si

el coeficiente de rozamiento para el cuerpo vale 0,4 y realice un gráfico indicando las fuerzas indicando las fuerzas que actúan el en armario.

1 answer:

aalyn [17]2 years ago

4 0

Responder:

470.4N

Explicación:

La fuerza de fricción se expresa mediante la fórmula;

Ff = nR

n es el coeficiente de fricción

R es la reacción

R = peso = mg

Ff = nmg

Dado

n = 0,4

masa m = 120kg

g es la aceleración debida a la gravedad = 9,8 m / s²

Sustituir en la fórmula;

Ff = 0,4 (120) (9,8)

Ff = 470,4 N

Por tanto, la fuerza de fricción es 470,4 N

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