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Nonamiya [84]
3 years ago
11

What is the force required to produce an acceleration of 46.4

Physics
1 answer:
Brilliant_brown [7]3 years ago
7 0
That depends on the mass of the object, and the unit of the '46.4' .

If the '46.4' is ' meters per second² ' , then the force required is

       (mass of the object in kilograms) x (46.4)    newtons .

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<h3>Answer:</h3>

209.236 kg · m/s

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Physics</u>

<u>Momentum</u>

Momentum Formula: P = mv

  • P is momentum (in kg · m/s)
  • m is mass (in kg)
  • v is velocity (in m/s)
<h3>Explanation:</h3>

<u>Step 1: Define</u>

m₁ = 87.2 kg

v₁ = 2.87 m/s

m₂ = 0.0520 kg

v₂ = 789 m/s

<u>Step 2: Find Momentums</u>

<em>Football Player</em>

  1. Substitute [MF]:                    P = (87.2 kg)(2.87 m/s)
  2. Multiply:                                P = 250.264 kg · m/s

<em>Bullet</em>

  1. Substitute [MF]:                    P = (0.0520 kg)(789 m/s)
  2. Multiply:                                P = 41.028 kg · m/s

<u>Step 3: Find difference</u>

  1. Define equation:                    P₁ - P₂
  2. Substitute:                              250.264 kg · m/s - 41.028 kg · m/s
  3. Subtract:                                 209.236 kg · m/s
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Three boxes in contact rest side-by-side on a smooth, horizontal floor. Their masses are 5.0-kg, 3.0-kg, and 2.0-kg, with the 3.
Ivahew [28]

Answer:

(a)Look at the attached graphic

(b)

(b)-1 Equation 1  : m1= 5kg

       50-F1= 5 *a

(b)-2 Equation 2 : m2= 3kg

        F1-F2= 3 *a

(b)-3 Equation 3 : m3= 2kg

         F2 = 2*a  

(c) F1 =25 N

(d) F2 =10 N

Explanation:

We apply Newton's second law:

∑F = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

(a) Draw the free-body diagrams for each of the boxes

Look at the attached graphic

(b) Write Newton’s equation for each mass along the horizontal direction.

Data: m1=  5.0-kg ,m2= 3.0-kg , ,m3= 2.0-kg

<em>Look</em> <em>m1 free-body diagram:</em>

∑Fx = m1*a

50-F1= 5 *a Equation 1

<em>Look</em> <em>m2 free-body diagram:</em>

∑Fx = m2*a

F1-F2= 3 *a Equation 2

<em>Look</em> <em>m3 free-body diagram:</em>

∑Fx = m3*a

F2 = 2*a     Equation 3

(c) What magnitude force does the 3.0-kg box exert on the 5.0- kg box?

<em>Look</em> <em>Free body diagram of the mass set</em>

∑Fx = m*a   m= m1+m2+m3= 5+3+2 = 10 kg

50 = 10*a

a= 50/10 = 5 m/s²

We replace a = 5 m/s² in the equation 1:

50-F1= 5 *5

50-25= F1

F1 = 25 N

<em> (d) </em><em>What magnitude force does the 3.0-kg box exert on the 2.0kg box?</em>

We replace a= 5 m/s² in the equation 3

F2 = 2*5 = 10 N

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3 years ago
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