An experimental arrangement for measuring the thermal conductivity of solid materials involves the use of two long rods that are
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Answer:
prove that | S | = | E | ; every element of S there is an Image on E , while not every element on E has an image on S
Explanation:
Given that S = { p q |p, q are prime numbers greater than 0}
E = {0, −2, 2, −4, 4, −6, 6, · · · }
To prove by constructing a bijection from S to E
detailed solution attached below
After the bijection :
<em>prove that | S | = | E |</em> : every element of S there is an Image on E , while not every element on E has an image on S
∴ we can say sets E and S are infinite sets
Answer with Explanation:
Assuming that the degree of consolidation is less than 60% the relation between time factor and the degree of consolidation is
Solving for 'U' we get
Since our assumption is correct thus we conclude that degree of consolidation is 50.46%
The consolidation at different level's is obtained from the attached graph corresponding to Tv = 0.2
i) = 71% consolidation
ii) = 45% consolidation
iii) = 30% consolidation
Part b)
The degree of consolidation is given by
Thus a settlement of 50.46 centimeters has occurred
For time factor 0.7, U is given by
thus consolidation of 85.59 % has occured if time factor is 0.7
The degree of consolidation is given by
Answer:
The rest is straightforward...