Waves interact with matter in several ways. The interactions occur when waves pass from one medium to another. Besides bouncing back like an echo, waves may bend or spread out when they strike a new medium. These three ways that waves may interact with matter are called reflection, refraction, and diffraction.
Answer:
The atomic mass of X is 204.5 amu.
Explanation:
We know that metals react with oxygen forming a metallic oxide, according to the following equation:
4 X + O₂ ⇄ 2 X₂O
The oxide is formed just by <em>just</em> two elements, the metal and oxygen. The total mass of the oxide is 1.4158g and the mass of the metal in the oxide must be 1.3625g because of the Law of conservation of mass. Then, we can substract the mass of the metal to obtain the mass of oxygen.
mass O + mass X = mass X₂O
mass O = mass X₂O - mass X = 1.4158g - 1.3625g = 0.0533g
So, for every 0.0533g of oxygen there are 1.3625 g of the metal X. In the formula X₂O there is 1 mol of atoms of oxygen, which has a molar mass of 16 g/mol. We can use this data to find out the mass of the metal in the oxide.
Given in the formula there are 2 moles of atoms of X, the molar mass should be half of 409g, i.e., 204.5g/mol. If a mol of X has a mass of 204.5 g, an atom of X has a mass of 204.5 amu, according to its definition.
Explanation:
When your blood circulates through your digestive system, for example, it picks up nutrients your body absorbed from your last meal. Your blood also carries oxygen inhaled by the lungs.
What is number one i might answer if you tell me
The compound that is involved in the reaction with silver nitrate to form silver chloride and iron (III) nitrate is Iron (III) chloride.
<h3>What is a displacement reaction?</h3><h3 />
The displacement reaction is the one in which the more reactive element displaces the less reactive element from the compound forming a new compound.
The formation of silver chloride and iron (III) nitrate was followed by the double displacement reaction. The silver in silver nitrate was replaced by the iron forming iron(III) nitrate, and the chloride from the Iron chloride reacted with silver forming silver chloride.
Thus, the compound that reacts with Silver nitrate in the double displacement reaction is Iron(III) chloride.
Learn more about displacement reaction, here:
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