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DochEvi [55]
2 years ago
12

What is the ionic equation for HC2H3O2(aq)+NH4OH(aq)=NH4C2H3O2(aq)+H2O

Chemistry
1 answer:
kondaur [170]2 years ago
5 0

Answer:

Ionic equation:

H⁺(aq)  + C₂H₃O₂⁻ (aq) + NH₄⁺(aq)  + OH⁻(aq)     →    NH₄⁺(aq)  + C₂H₃O₂⁻ (aq) +  H₂O(l)

Explanation:

Chemical equation:

HC₂H₃O₂(aq) + NH₄OH(aq) → NH₄C₂H₃O₂(aq) + H₂O(l)

Ionic equation:

H⁺(aq)  + C₂H₃O₂⁻ (aq) + NH₄⁺(aq)  + OH⁻(aq)     →    NH₄⁺(aq)  + C₂H₃O₂⁻ (aq) +  H₂O(l)

Net ionic equation:

H⁺(aq)  + OH⁻(aq)     →     H₂O(l)

The C₂H₃O₂⁻ (aq) and NH₄⁺(aq) and are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

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Fumaric acid, which occurs in many plants, contains, by mass, 41.4% carbon, 3.47% hydrogen, and 55.1% oxygen. The molecular mass
lukranit [14]

Answer:

Explanation:

C = 41.4/12 = 3.43

H = 3.47/1 = 3.47

O = 55.1/16 =3.44

CHO is the skeletal formula (divide each by the lowest number above). The results are close enough to 1 to be 1.

(CHO)_x = 116

C + H + O = 29

(29) _ x = 116

x = 116/29

x = 4

So there area 4 carbons 4 hydrogens and 4 oxygens.

The correct formula is C4H4O4

3 0
2 years ago
an aqueous solution contains 1.2mM of total ions. if the solution is NaCl (aq), what is the concentration of chloride ions?
Genrish500 [490]

Explanation:

As the total concentration is given as 1.2 mM. And, it is also given that salt present in the solution is NaCl.

As sodium chloride is an ionic compound so, when it is added to water then it will dissociate into sodium and chlorine ions as follows.

           NaCl \rightarrow Na^{+} + Cl^{-}

So, it means in total there will be formation of 2 ions when one molecules of NaCl dissociates.

Therefore, concentration of chlorine ions will be calculated as follows.

       Concentration of Cl^{-} ions = \frac{1.2mM}{2}

                                                        = 0.6 mM

Thus, we can conclude that the concentration of chloride ions is 0.6 mM.

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