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DochEvi [55]
3 years ago
12

What is the ionic equation for HC2H3O2(aq)+NH4OH(aq)=NH4C2H3O2(aq)+H2O

Chemistry
1 answer:
kondaur [170]3 years ago
5 0

Answer:

Ionic equation:

H⁺(aq)  + C₂H₃O₂⁻ (aq) + NH₄⁺(aq)  + OH⁻(aq)     →    NH₄⁺(aq)  + C₂H₃O₂⁻ (aq) +  H₂O(l)

Explanation:

Chemical equation:

HC₂H₃O₂(aq) + NH₄OH(aq) → NH₄C₂H₃O₂(aq) + H₂O(l)

Ionic equation:

H⁺(aq)  + C₂H₃O₂⁻ (aq) + NH₄⁺(aq)  + OH⁻(aq)     →    NH₄⁺(aq)  + C₂H₃O₂⁻ (aq) +  H₂O(l)

Net ionic equation:

H⁺(aq)  + OH⁻(aq)     →     H₂O(l)

The C₂H₃O₂⁻ (aq) and NH₄⁺(aq) and are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

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_______ properties depend on the concentration of a solute in a solution but not on the identity of the solute.
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This problem is providing us with a statement in which we need to figure out the word fitting in the blank. At the end, after analyzing the information, the word turns out to be colligative as show below:

<h3>Colligative properties.</h3>

In chemistry, colligative properties of solutions account for the behavior of a solution with respect to the pure solvent, to which a solute is added.

Among them, we have boiling point elevation, freezing point depression, vapor pressure lowering and osmotic pressure, which are all affected by the concentration of the solute but not by the identity of the solute.

In such a way, we conclude that the correct word that fits in the blank is colligative as shown below:

"Colligative properties depend on the concentration of a solute in a solution but not on the identity of the solute."

Learn more about colligative properties: brainly.com/question/10323760

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2 years ago
Why is a changing ocean temperature of only one or 2 degrees so concerning?
gregori [183]
<span>One degree Celsius indicates the same temperature change as one </span>
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Copper wire is used in electrical wiring because the metallic bonding between the atoms aids with the ___________ of the materia
Darya [45]

electrons can move freely through the material

7 0
3 years ago
List the following aqueous solutions in order of decreasing freezing point: 0.040 m glycerin (C3H8O3), 0.020 m potassium bromide
gogolik [260]

Answer:

Solutions from highest to lowest freezing point:

0.040 m glycerin = 0.020 m potassium bromide > 0.030 m phenol

Explanation:

\Delta T_f=i\times K_f\times m

\Delta T_f = Depression in freezing point

i = van'T Hoff fcator

K_f = Molal depression constant of solvent

m = molality of the solution

Higher the value of depression in freezing point at  lower will be freezing temperature the solution.

1. 0.040 m glycerin

Molal depression constant of water = K_f=1.86^oC/m

i = 1 ( organic molecule)

m = 0.040 m

\Delta T_{f,1}=1\times\times 1.86^oC/m\times 0.040 m

\Delta T_{f,1}=0.0744^oC

2. 0.020 m potassium bromide

Molal depression constant of water = K_f=1.86^oC/m

i = 2 (ionic)

m = 0.020 m

\Delta T_{f,2}=2\times\times 1.86^oC/m\times 0.020 m

\Delta T_{f,2}=0.0744^oC

3. 0.030 m phenol

Molal depression constant of water = K_f=1.86^oC/m

i = 1 (organic)

m = 0.030 m

\Delta T_{f,3}=1\times\times 1.86^oC/m\times 0.030 m

\Delta T_{f,3}=0.0558^oC

0.0744^oC=0.0744^oC > 0.0558^oC

\Delta T_{f,1}=\Delta T_{f,2}>\Delta T_{f,3}

Solutions from highest to lowest freezing point:

0.040 m glycerin = 0.020 m potassium bromide > 0.030 m phenol

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3 years ago
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Actinium-silvery
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