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Harman [31]
2 years ago
6

Joinn my zo om lets play some blookets 98867 708157 9dPQPW

Chemistry
2 answers:
liubo4ka [24]2 years ago
7 0

Answer:

whats blookets

Explanation:

ahrayia [7]2 years ago
3 0

Answer:that sounds very tempting

Explanation:

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This biome has the nutrient poor soil
nikklg [1K]

Answer:

the answer is the tropical rain forest

7 0
3 years ago
Claire is investigating potential and kinetic energy using a large ball. For her investigation, Claire will stand at the top of
uranmaximum [27]

The ball's potential energy will decrease, and its kinetic energy will increase.

Explanation:

The ball's potential energy will decrease down the slope and its kinetic energy will increase.

Kinetic energy is the energy due to the motion of a body.

 K. E = \frac{1}{2} m v²

 m is the mass of the ball

  v is the velocity of the ball.

Potential energy is the energy due to the motion of a body down slope.

It is expressed as:

   P.E = mgh

  m is the mass of ball

   g is the acceleration due to gravity of the body

  h is the height.

We can see as the body drops down the slope, the height diminishes and the velocity increases.

learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

3 0
3 years ago
Red giant stars defination​
kramer

Answer:

A red giant is a luminous giant star of low or intermediate mass in a late phase of stellar evolution. The outer atmosphere is inflated and tenuous, making the radius large and the surface temperature around 5,000 K or lower.

6 0
2 years ago
Read 2 more answers
A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr
sertanlavr [38]

Answer: The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.947 atm

P_2 = final pressure of gas = 0.987 atm

V_1 = initial volume of gas = 150 ml

V_2 = final volume of gas = 144 ml    

T_1 = initial temperature of gas = 25^0C=(25+273.15)K=298.15K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}

T_2=298.31K=(298.31-273.15)^0C=25.16^0C

The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

4 0
2 years ago
What is the percent by mass of Fluorine in Nitrogen triflouride NF3?
Kipish [7]

Answer:

The answer to your question is 80.3%

Explanation:

Data

Percent by mass of F

molecules NF₃

Process

1.- Calculate the molar mass of nitrogen trifluoride

molar mass = (1 x 14) + (19 x 3)

                    = 14 + 57

                    = 71 g

2.- Use proportions and cross multiplications to find the percent by mass of F. The molar mass of NF₃ is equal to 100%.

                       71 g of NF₃ ------------------ 100%

                       57 g of F   ------------------- x

                            x = (57 x 100)/71

                            x = 5700 / 71

                            x = 80.3%

3.- Conclusion

Fluorine is 80.3% by mass of the molecule NF₃

           

3 0
3 years ago
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