<span>4.200 calories. The formula is rise in heat (H) = the specific heat capacity (c) * rise in heat in degrees Fahrenheit (T) and volume of liquid (m) . H= cTm. Water, the typical comparison, has a specific heat capacity of 1. So to raise the Fahrenheit temperature of 105 grams of water 40 degrees, you multiply 105 * 40 * 1 = 4,200.</span>
Answer:
Balanced chemical equation:
AgCl + 2KCN → K[Ag(CN)₂] (aq) + KCl (aq)
Balanced chemical equation:
2Al + 6NaOH →2 Na₃AlO₃ + 3H₂
Explanation:
Chemical equation:
AgCl + KCN → K[Ag(CN)₂] (aq) + KCl (aq)
Balanced chemical equation:
AgCl + 2KCN → K[Ag(CN)₂] (aq) + KCl (aq)
Net ionic equation can not be written because all are present in aqueous form and no precipitation occur.
Chemical equation:
Al + NaOH → Na₃AlO₃ + H₂
Balanced chemical equation:
2Al + 6NaOH →2 Na₃AlO₃ + 3H₂
This is oxidation reduction reaction.
Hydrogen is reduced in this reaction. while aluminium is oxidized.
20 g/cm3 I got this because 120 divided by 6 is 20
Answer:
0.99%
Explanation:
The Henderson-Hasselbalch equation relates the ratio of the ionized to the non-ionized form of an acid as follows:
pH = pKa + log([A⁻]/[HA])
Inserting the values for pH and pKa and solving gives:
7.4 = 5.2 + log([A⁻]/[HA])
2 = log([A⁻]/[HA])
[A⁻]/[HA] = 100/1
The percentage of the weak acid in non-ionized form (HA) is then calculated:
[HA]/([A⁻] + [HA]) = 1/(100+1) x 100% = 0.99&
The atomic mass of rubidium listed in the periodic table to determine the mass of Rb−87 is 86.13 amu.
<h3>What is atomic mass?</h3>
The atomic mass is the weight of the roton neutron and electron present inside the nucleus and shells of an atom and the elements are arranged on the basis of this only.
The mass of Rb−85 is 84.9118 amu for 1 amu it will be
amu = 84.9118 / 85 = 0.99
so, the amu for Rb−87 will be,
AMU = 87 × 0.99 = 86.13 amu.
Therefore, the mass of Rb−87 is 86.13 amu for atomic mass of rubidium listed in the periodic table.
Learn more about atomic mass, here:
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