Answer:
P = 14.1 atm
Explanation:
Given data:
Mass of methane = 64 g
pressure exerted by water vapors = ?
Volume of engine = 24.0 L
Temperature = 515 K
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O + energy
Number of moles of methane:
Number of moles = mass / molar mass
number of moles = 64 g/ 16 g/mol
Number of moles = 4 mol
Now we will compare the moles of water vapors and methane.
CH₄ : H₂O
1 : 2
4 : 2/1×4 = 8 mol
Pressure of water vapors:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
P = 8 mol × 0.0821 atm.L/mol.K× 515 K / 24.0 L
P = 338.25 atm.L/ / 24.0 L
P = 14.1 atm
Answer:
molecular weight of NH3 or grams This compound is also known as Ammonia. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles NH3, or 17.03052 grams.
Answer:
Thermal decomposition or cracking
Explanation:
Petroleum is a mixture of hydrocarbons which are usually formed naturally. Petroleum undergo a host of chemical reactions. One of such is thermal decomposition or cracking.
Cracking is used in the petroleum industry to covert heavy fractions to more useful lighter ones.
When petroleum is subjected to high temperature and pressure, and in the presence of catalyst, the long chain type of petroleum will decompose into more useful smaller and lighter molecules.
Example is given below:
C₁₅H₃₂ → C₈H₁₈ + C₃H₆ + 2C₂H₄
1.56 moles of N2 are needed to fill a 35 L tank at standard temperature and pressure. Details about moles can be found below.
<h3>How to calculate number of moles?</h3>
The number of moles of a substance can be calculated using the following formula:
PV = nRT
Where;
- P = pressure
- V = volume
- n = number of moles
- R = gas law constant
- T = temperature
At STP;
- T = 273K
- P = 1 atm
- R = 0.0821 Latm/molK
1 × 35 = n × 0.0821 × 273
35 = 22.41n
n = 35/22.41
n = 1.56mol
Therefore, 1.56 moles of N2 are needed to fill a 35 L tank at standard temperature and pressure.
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