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Vera_Pavlovna [14]
3 years ago
8

Communication with submerged submarines via radio waves is difficult because seawater is conductive and absorbs electromagnetic

waves. Penetration into the ocean is greater at longer wavelengths, so the United States has radio installations that transmit at 76Hz for submarine communications.What is the approximate wavelength of those extremely low-frequency waves?500 km1000 km2000 km4000 km
Physics
1 answer:
REY [17]3 years ago
4 0

Answer:

\lambda=4000\ km

Explanation:

It is given that,

Frequency for submarine communications, f = 76 Hz

We need to find the wavelength of those extremely low-frequency waves. the relation between the wavelength and the frequency is given by :

c=f\times \lambda

\lambda=\dfrac{c}{f}

\lambda=\dfrac{3\times 10^8\ m/s}{76\ Hz}

\lambda=3947368.42\ m

\lambda=3947\ km

or

\lambda=4000\ km

So, the wavelength of those extremely low-frequency waves is 4000 km. Hence, this is the required solution.

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3 years ago
You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 286.0 kPa when the ther
diamong [38]

Answer:

T_{2} = 606.69 K

Explanation:

In that the gas thermometer is a constant volume, it is satisfied that:

\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }  

How the boiling water is under regular atmospheric pressure, then

T_{1} = 373 .15 K

Thus

\frac{286000}{373.15} = \frac{465000}{T_{2} }

T_{2} = 606.69 K

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3 years ago
In the drawing, water flows from a wide section of a pipe to a narrow section. In which part of the pipe is the volume flow rate
guapka [62]

Answer:

Volume flow rate is the same in both sections of the pipe

Explanation:

7 0
2 years ago
What is the weight of an object (mass = 60 kilograms) on Mars, where the acceleration due to gravity is 3.75 meters/second2?. Se
77julia77 [94]
Weight = mass * gravity = 60 kg * 3.75 m/s² = 225 N

<span>Option D.</span>
7 0
3 years ago
A block of mass m = 2.0 kg slides head on into a spring of spring constant k = 260 N/m. When the block stops, it has compressed
nasty-shy [4]

Answer:

a) Ws = 2.548 J

b) Wf = 1.153 J

c) v = 1.923 m / s

Explanation:

a) The work done by the spring force  

Ws =  ½ * k * x²

Ws =  ½ * 260 N/m *0.14² m  

Ws =  2.548J

b) The increase in thermal energy can by find using  

Et = Wf

Wf = µ * m *g * x  

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c) The speed just as the block reaches can by fin using

EK = Ws + Et

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Ek = ½ * m * v²

v² = 2* Ek / m

v = √[2 * 3.7 J / 2.0 kg]

v = 1.923 m / s

8 0
3 years ago
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