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Anna35 [415]
3 years ago
6

Imagine you have an object with a non-geometric shape having a mass of 26.7 g and

Chemistry
1 answer:
Bas_tet [7]3 years ago
7 0

Answer:

The new reading of the water level is 54.81 mL.

Explanation:

From the question given above, the following data were obtained:

Mass of object = 26.7 g

Density of object = 0.767 g/mL

Volume of water = 20 mL

New reading of the water level =?

Next, we shall determine the volume of the object. This can be obtained as follow:

Mass of object = 26.7 g

Density of object = 0.767 g/mL

Volume of object =?

Density = mass /volume

0.767 = 26.7 / volume of object

Cross multiply

0.767 × Volume of object = 26.7

Divide both side by 0.767

Volume of object = 26.7 / 0.767

Volume of object = 34.81 mL

Finally, we shall determine the new reading of the water level. This can be obtained as follow:

Volume of water = 20 mL

Volume of object = 34.81 mL

New reading of the water level =?

New reading of the water level = (Volume of water) + (Volume of object)

New reading = 20 + 34.81

New reading of the water level = 54.81 mL

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what ph indicator is added to the simmons citrate agar? group of answer choices phenol red methylene green bromothymol blue litm
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