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3 years ago

If the salt created from the reaction of a strong acid and a weak base is added to a solution, what will happen to the solution

Chemistry

1 answer:

hoa [83]3 years ago

4 0

Answer:

See Explanation

Explanation:

When a salt is dissolved in water, the solution could be acidic, basic or neutral depending on the nature of acid and base from which the salt was formed.

When a salt is formed from a strong acid and a weak base, the salt solution is acidic.

For instance, NH4Cl is a salt formed from NH3 which is a weak base and HCl which is a strong acid. The salt hydrolyses as follows;

NH4^+(aq) + H2O(l) ------> H3O^+(aq) + NH3(aq)

Hence an acidic solution is formed.

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H2PO4-(aq) ⇆ H+(aq) + HPO42-( which ion plays the role of hydrogen ion donor and which one plays the hydrogen ion acceptor in BP

alexgriva [62]

Answer:

H2PO4- is a proton donor and HPO42_ is a proton acceptor

Explanation:

Step 1: What are hydrogen ion donor and acceptor

in the following reaction we see that:

⇒ H2PO4- is more likely to give a H+ ion to form HPO42-.

⇒HPO42- is more likely to take a H+ ion, to form H2PO4-

The reaction of an acid in water solvent is described as a dissociation :

HA ⇔ H+ + A-

⇒where HA is a proton acid

So, H2PO4- = HA and HPO42- = A-

Acids are proton donors. So, H2PO4- is a proton donor and HPO42_ is a proton acceptor

6 0

3 years ago

Energy leaves the sun as light from region called the?

tino4ka555 [31]

Late answer:
Chromosphere.

4 0

3 years ago

For the overall reaction below, which of the following is the correctly written rate law? Overall reaction: O3(g)+2NO2(g)→N2O5(g

zavuch27 [327]

Answer: $Rate=k[O_3][NO_2]^2$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$O_3(g)+NO_2(g)\rightarrow NO_3(g)+O_2(g)$ slow

$NO_3(g)+NO_2(g)\rightarrow N_2O_5(g)$ fast

To determine the net chemical equation, we will simply add the above two equations, we get:

$O_3(g)+2NO_2(g)\rightarrow N_2O_5(g)+O_2(g)$

$Rate=k[O_3][NO_2]^2$

Order with respect to $O_3$ is 1 and Order with respect to $NO_2$ is 2.

Thus the rate law will be: $Rate=k[O_3][NO_2]^2$

6 0

3 years ago

With respect to a fixed point, motion is defined as a change in- A)speed B)position

Arisa [49]

Answer:

With respect to a fixed point, motion is defined as a change in position.

Explanation:

MOTION -: Motion is described as the fact in which any object or body changes its position over the time with respect to a fixed point .

Motion is defined as displacement, distance, velocity , acceleration, speed , and time in mathematical terms. By linking an observer to a frame of reference and measuring the shift in the position of the body with a change in time relative to that frame, the motion of a body is observed.

4 0

3 years ago

I was checking my answers for a chem test and came across a solution for a problem where the ∆S was pos, ∆H was neg and ∆G was n

nevsk [136]

Answer:

there is only 15 points

Explanation:

The second law of thermodynamics says that the entropy of the universe always increases for a spontaneous process: \Delta \text {S}_{\text{universe}}=\Delta \text {S}_{\text{system}} + \Delta \text {S}_{\text{surroundings}} > 0ΔS

universe

=ΔS

system

+ΔS

surroundings

>0delta, start text, S, end text, start subscript, start text, u, n, i, v, e, r, s, e, end text, end subscript, equals, delta, start text, S, end text, start subscript, start text, s, y, s, t, e, m, end text, end subscript, plus, delta, start text, S, end text, start subscript, start text, s, u, r, r, o, u, n, d, i, n, g, s, end text, end subscript, is greater than, 0

At constant temperature and pressure, the change in Gibbs free energy is defined as \Delta \text G = \Delta \text H - \text{T}\Delta \text SΔG=ΔH−TΔSdelta, start text, G, end text, equals, delta, start text, H, end text, minus, start text, T, end text, delta, start text, S, end text.

When \Delta \text GΔGdelta, start text, G, end text is negative, a process will proceed spontaneously and is referred to as exergonic.

The spontaneity of a process can depend on the temperature.

Spontaneous processes

In chemistry, a spontaneous processes is one that occurs without the addition of external energy. A spontaneous process may take place quickly or slowly, because spontaneity is not related to kinetics or reaction rate. A classic example is the process of carbon in the form of a diamond turning into graphite, which can be written as the following reaction:

8 0

3 years ago