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djverab [1.8K]
3 years ago
15

Identify the type of reaction: 2AgCl + BaBr2 -> 2AgBr + BaCl2

Chemistry
1 answer:
Marta_Voda [28]3 years ago
6 0

Answer:

C

Explanation:

Just look at the reactants.

2AgCl + BaBr2

The first reactant is made of 2 elements.

The second reactant is made of 2 elements.

It can't be a decomposition. At this level there is only one reactant made of 2 elements. Something like

2MgO ===> 2Mg + O2

is a decomposition.  One compound breaking down into 2 elements Mg and O.

It can't be a combustion. One of the reactants in a combustion is oxygen. Those equations look like

C3H8 + 5O2 ==> 3CO2 + 4H2O

That would be what a combustion looks like

It can't be a single replacement. They look like

Mg + CuO ===> Cu + MgO

There are elements on both sides of the reaction.

that leaves a double replacement which I wrote about how you distinguish it.

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Which of the following lists elements from lowest to highest atomic number?
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Answer:

The last option  V, Rh, Sn

Explanation:

Look at the periodic table.  Atomic weight increases going from left to right and progressing downward in the table.

5 0
3 years ago
A gas at 300 k and 4.0 atm is moved to a new location with a temperature of 250 k. the volume changes from 5.5 l to 2.0 l. what
ella [17]

Answer:

9.17 atm

Explanation:

To find the new pressure of the gas, you need to use the following manipulated formula:

P₁V₁ / T₁ = P₂V₂ / T₂

In this formula,

P₁ = initial pressure (atm)              P₂ = new pressure (atm)

V₁ = initial volume (L)                    V₂ = new volume (L)

T₁ = initial temperature (K)            T₂ = new temperature (K)

Because you have been given values for all of the variables except for the new pressure, you can substitute them into the equation and simplify.

P₁ = 4.0 atm                                  P₂ = ? atm

V₁ = 5.5 L                                      V₂ = 2.0 L

T₁ = 300 K                                     T₂ = 250 K

P₁V₁ / T₁ = P₂V₂ / T₂                                                     <----- Given formula

(4.0 atm)(5.5 L) / (300 K) = P₂(2.0 L) / (250 K)           <----- Insert variables

0.073333 = P₂(2.0 L) / (250 K)                                   <----- Simplify left side

18.33333 = P₂(2.0 L)                                     <----- Multiply both sides by 250

9.17 = P₂                                                        <----- Divide both sides by 2.0

5 0
2 years ago
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Answer:

I need the table to do the question

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7 0
3 years ago
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aev [14]

Answer:

True

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All the above statements buttress the fact that the larger molecule, the greater the magnitude of London forces between the molecules. Each of the statements above is a confirmation/explanation of this general rule.

6 0
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6 0
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