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3 years ago

Prove 1/P = 1/P1 + 1/P2

Physics

1 answer:

Sati [7]3 years ago

7 0

Answer:

Proof:

|----------(R1)-------------(R2)---------|

Let the resistances be R1 , R2 connected in series. And the potential difference be V ;

We know that :

P1 = V²/R1 ..........(1) and

P2 = V²/R2 ...........(2)

In series combination , the net resistance is the algebraic addition of individual resistance :

R = R1 + R2

=> V²/P = V²/P1 + V²/P2

=> 1/P = 1/P1 + 1/P2

Explanation:

Copied it from a different brainly question that is this question. Please try to find it on brainly instead of asking it'd make it much easier.

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A 68 kg object, starting from rest, travels from point A to point B at a rate of 30 m/s in 2 hours. What is the applied force on

Natasha2012 [34]

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$\huge\boxed{\sf F = 0.28\ N}$

Explanation:

<h3>Given Data:</h3>

Mass = m = 68 kg

Velocity = v = 30 m/s

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<h3>Required:</h3>

Force = F = ?

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$\displaystyle F = \frac{mv}{t}$

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1 year ago

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics

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Answer:

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3 years ago