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3 years ago

Please help ASAP! I will give the first answer brainliest!

Physics

1 answer:

Natalija [7]3 years ago

3 0

Answer:

Sorry for being late. Hope this helps

Explanation:

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a sphere of diameter 6•0cm is moulded into a thin uniform wire of diameter 0•2mm.calculate the length of the wire in metres

Scilla [17]

The length of the wire is 36 m.

Explanation:

Given, Diameter of sphere = 6 cm

We know that, radius can be found by taking the half in the diameter value. So,

$\text { sphere radius, } R=\frac{D}{2}=\frac{6}{2}=3 \mathrm{cm}=3 \times 10^{-2} \mathrm{m}$

Similarly,

$\text { wire radius, } r=\frac{0.2}{2}=0.1 \mathrm{mm}=1 \times 10^{-3} \mathrm{m}$

We know the below formulas,

$\text {volume of sphere}=\frac{4}{3} \times \pi \times R^{3}$

$\text {volume of wire}=\pi \times r^{2} \times l$

When equating both the equations, we can find length of wire as below, where $\pi=\frac{22}{7}$

$\frac{4}{3} \times \pi \times R^{3}=\pi \times r^{2} \times l$

$\frac{4}{3} \times \frac{22}{7} \times\left(3 \times 10^{-2}\right)^{3}=\frac{22}{7} \times\left(1 \times 10^{-3}\right)^{2} \times l$

The $\pi$ value gets cancelled as common on both sides, we get

$\frac{4}{3} \times 27 \times 10^{-6}=10^{-6} \times l$

The $10^{-6}$ value gets cancelled as common on both sides, we get

$l=4 \times 9=36 m$

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3 years ago

If an automobile engine delivers a power of 50.0 hp, how much time will it take for the engine to do 6.40 x 10^4 j of work? (1 h

aleksandrvk [35]

Given data

Power (P) = 50 hp,

= 50 × 746, we know that 1 hp = 746 W.

= 37300 Watts (Watt = J/s)

Work = 6.40 ×10⁴ J

Power is defined as rate of doing work and the unit of power is Watt.

Mathematically,

Power = (Work / time) Watts

= 6.40 ×10⁴ / time

37300 W = 6.40 ×10⁴ J /time (Where time in seconds)

=> time = Work/Power

= 6.40 ×10⁴/37300

= 1.74 seconds

Therefore , the engine need 1.74 seconds to do 6.40 6.40 ×10⁴ J of work 

 

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lys-0071 [83]

Answer:

True

Explanation:

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