Answer:
Explanation:
Half life T is 432 years .
432 years = 432 x 365 x 24 x 60 x 60 s
= 1.36 x 10¹⁰ s .
No of atoms in 5.54 g of sample of Am N= 6.02 x 10²³ x 5.54 / 241
N = 138.38 x 10²⁰ atoms .
disintegration constant λ = .693 / half life
λ = .693 / 1.36 x 10¹⁰ s .
= .51 x 10⁻¹⁰ .
dN / dt = λN
= .51 x 10⁻¹⁰ x 138.38 x 10²⁰
= 70.57 x 10¹⁰ per second.
No of particles emitted = no of disintegration per second
No of particles emitted = 70.57 x 10¹⁰ per second.
