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irga5000 [103]
3 years ago
14

Identify the major force between molecules of pentane and hexane

Chemistry
1 answer:
Ilya [14]3 years ago
6 0

Answer:

induced-dipole induced dipole forces.

Explanation:

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What is 9872002 in scientific notation?
frutty [35]

Answer:

= 9.872002 × 10^6

Explanation:

Move the decimal point in your number until there is only one non-zero digit to the left of the decimal point. The resulting decimal number is a.

Count how many places you moved the decimal point. This number is b.

If you moved the decimal to the left b is positive.

If you moved the decimal to the right b is negative.

If you did not need to move the decimal b = 0.

Write your scientific notation number as a x 10^b and read it as "a times 10 to the power of b."

Remove trailing 0's only if they were originally to the left of the decimal point.

7 0
3 years ago
Read 2 more answers
For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi
natka813 [3]

<u>Answer:</u> The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ....(1)

  • <u>For Iron:</u>

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:  

\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol

For the given chemical reaction:

2Fe(s)+O_2(g)\rightarrow 2FeO(s)

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = \frac{2}{2}\times 0.0771=0.0771mol of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:  

0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g

To calculate the percentage yield of iron (ii) oxide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0
3 years ago
Which two types of information are found in an element's box in the periodic
asambeis [7]

Answer:

The answer is B and D.

Explanation:

prove me wrong

4 0
3 years ago
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Covalent compounds do not conduct electric current in a water solution well because they _____.
siniylev [52]
Covalent compounds do not conduct electric current in a water solution well because they do not dissociate into ions.
5 0
3 years ago
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Given the reaction below, if 0.00345 g of carbon dioxide is used up, how many grams of water will be produced?
zimovet [89]

From the  stoichiometry of the reaction, 1.4 * 10^-3 g is produced.

<h3>What mass of water is produced?</h3>

The equation of the reaction is written as; CO2 + 2LiOH → Li2CO3 + H2O. This can help us to apply the principle of stoichiometry here.

Thus;

Number of moles of CO2 = 0.00345 g/44 g/mol = 7.8 * 10^-5 moles

If 1 mole of CO2 produced 1 mole of water

7.8 * 10^-5 moles of CO2 produced  7.8 * 10^-5 moles of water

Mass of water produced =  7.8 * 10^-5 moles * 18 g/mol = 1.4 * 10^-3 g

Learn ore about stoichiometry:brainly.com/question/9743981

#SPJ1

3 0
2 years ago
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