Most of the energy will be absorbed by the materials that make up the cars, causing them to deform. The energy will also be converted into sound energy, causing a loud bang upon collision. Also, some energy will be converted to thermal energy, which will cause the cars to heat up slightly.
        
             
        
        
        
For the front glass of the car to get wet,  .
.
The given parameters:
- <em>Speed of the car, = Vc</em>
- <em>Speed of the rain, = 10 m/s</em>
The relative velocity of the car with respect to the falling rain is calculated as;

- If the speed of the car equals the speed of the rain, the rain will fall behind the car.
- If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.
- If the speed of the car is greater than speed of the rain, the rain will fall on the car.
Thus, for the front glass of the car to get wet,  .
.
Learn more about relative velocity here: brainly.com/question/17228388
 
        
             
        
        
        
<span> Allied Forces. they became the allies.</span>
        
                    
             
        
        
        
Answer:
The temperature of the steam during the heat rejection process is 42.5°C 
Explanation:
Given the data in the question;
the maximum temperature T in the cycle is twice the minimum absolute temperature T
 in the cycle is twice the minimum absolute temperature T in the cycle
 in the cycle 
T = 0.5T
  = 0.5T 
 
now, we find the efficiency of the Carnot cycle engine
η = 1 - T
 = 1 - T /T
/T
η = 1 - T
 = 1 - T /0.5T
/0.5T
η = 0.5
 = 0.5
the efficiency of the Carnot heat engine can be expressed as;
η = 1 - W
 = 1 - W /Q
/Q
where W is net work done, Q
 is net work done, Q is is the heat supplied
 is is the heat supplied
we substitute
0.5 = 60 / Q
Q = 60 / 0.5
 = 60 / 0.5
Q = 120 kJ
 = 120 kJ
Now, we apply the first law of thermodynamics to the system
W = Q
 = Q - Q
 - Q
60 = 120 -  Q
Q = 60 kJ
 = 60 kJ
now, the amount of heat rejection per kg of steam is;
q = Q
 = Q /m
/m
we substitute
q = 60/0.025
 = 60/0.025
q = 2400 kJ/kg
 = 2400 kJ/kg
which means for 1 kilogram of conversion of saturated vapor to saturated liquid , it takes 2400 kJ/kg of heat ( enthalpy of vaporization)
q = h
 = h = 2400 kJ/kg
 = 2400 kJ/kg
now, at  h = 2400 kJ/kg from saturated water tables;
  = 2400 kJ/kg from saturated water tables;
T = 40 + ( 45 - 40 ) (
 = 40 + ( 45 - 40 ) (  )
 )
T = 40 + (5) × (0.5)
 = 40 + (5) × (0.5)
T = 40 + 2.5
 = 40 + 2.5
T = 42.5°C
 = 42.5°C   
Therefore, The temperature of the steam during the heat rejection process is 42.5°C