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3 years ago

Red: Distance = 3 x Time

Physics

1 answer:

sukhopar [10]3 years ago

5 0

2 because that’s correct I I I I I I I I I I I I I I I I I I I

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you place a 0.13kg can of soup and a 0.34kg jar of pickles on the kitchen counter separated by a distance of 0.42m. what is the

Nonamiya [84]

Answer:

1.67×10^-11 N

Explanation:

m1 = 0.13kg

m2 = 0.34kg

d = 0.42m

G = 6.674 × 10 ^−11

F = Gm1m2/r²

F= (6.674 × 10^ −11×0.13×0.34)/(0.42)²

F = 1.67×10^-11 N

4 0

4 years ago

What feature of the ocean basin is formed when old oceanic crust is forced under continental plates?

Sholpan [36]

Answer:

Mid ocean ridge is formed when old oceanic crust is forced under continental plates.

Explanation:

Ocean basin is a kind of land surface that is present under an ocean and below the water.

Ocean basin contain continental shelf,mid ocean ridge that is found on the sea floor.

The size of ocean basin is equal to the size of an ocean and is found below the ocean.

When, water covers the earth's crust region in the distant past,ocean basin formation occurs.This prcess require long time as spreading of sea floor and tectonic plates takes place.

Ex-Atlantic Ocean basin is formed over million years that is present in the European Continent.

4 0

4 years ago

CAN SOMEONE PLS HELP ME ILL GIVE YOU BRAINLIEST

-Dominant- [34]

Mass of the are is 2100 kg

8 0

3 years ago

Read 2 more answers

A small object with mass 1.30 kg is mounted on one end of arod

Julli [10]

Answer:

(a) $I_{system} = 1.014\ kg.m^{2}$

(b) $\tau = 0.0179\ N-m$

Solution:

As per the question:

Mass of the object, m = 1.30 kg

Length of the rod, L = 0.780 m

Angular speed, $\omega = 5010\ rev/min$

Now,

(a) To calculate the rotational inertia of the system about the axis of rotation:

Since, the rod is mass less, the moment of inertia of the rotating system and that of the object about the rotation axis will be equal:

$I_{system} = ML^{2} = 1.30\times (0.780)^{2} = 0.791\ kg.m^{2}$

(b) To calculate the applied torque required for the system to rotate at constant speed:

Drag Force, F = $2.30\times 10^{- 2}\ N$

$\tau = FLsin\theta 90 = 2.30\times 10^{- 2}\times 0.780\times 1 = 0.0179\ N-m$

3 0

3 years ago

In the first stage of a two-stage Carnot engine, energy is absorbed as heat Q1 at temperature T1 = 500 K, work W1 is done, and e

Nataly [62]

Answer:

Efficiency = 52%

Explanation:

Given:

First stage

heat absorbed, Q₁ at temperature T₁ = 500 K

Heat released, Q₂ at temperature T₂ = 430 K

and the work done is W₁

Second stage

Heat released, Q₂ at temperature T₂ = 430 K

Heat released, Q₃ at temperature T₃ = 240 K

and the work done is W₂

Total work done, W = W₁ + W₂

Now,

The efficiency is given as:

$\eta=\frac{\textup{Total\ work\ done}}{\textup{Energy\ provided}}$

Work done = change in heat

thus,

W₁ = Q₁ - Q₂

W₂ = Q₂ - Q₃

Thus,

$\eta=\frac{(Q_1-Q_2)\ +\ (Q_2-Q_3)}{Q_1}}$

$\eta=1-\frac{(Q_1-Q_3)}{Q_1}}$

$\eta=1-\frac{(Q_3)}{Q_1}}$

also,

$\frac{Q_1}{T_1}=\frac{Q_2}{T_2}=\frac{Q_3}{T_3}$

$\frac{T_3}{T_1}=\frac{Q_3}{Q_1}$

thus,

$\eta=1-\frac{(T_3)}{T_1}}$

thus,

$\eta=1-\frac{(240\ K)}{500\ K}}$

$\eta=0.52$

Efficiency = 52%

8 0

4 years ago