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Helga [31]
3 years ago
5

A compact car has a maximum acceleration of 2.0 m/s2 when it carries only the driver and has a total mass of 1100 kg . you may w

ant to review ( pages 108 - 109) . part a what is its maximum acceleration after picking up four passengers and their luggage, adding an additional 400 kg of mass
Physics
1 answer:
nadya68 [22]3 years ago
4 0

According to Newton`s  law. Force exerted by car,

F = m a = 1100 kg \times 2 m/s^2 = 2200 \ N

After adding an additional 400 kg of mass, the force will be same therefore the acceleration

F = 2200 \ N = (1100 \ kg + 400 \ kg)  a \\\\ a = \frac{2200 \ N}{1500 \ kg} = 1.47 \ m/s^2

Thus, the acceleration after adding the masses is 1.47 \ m/s^2.

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True or false if an object has energy it must be moving
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Answer:

Explanation:

If an object is moving, it is said to have kinetic energy (KE). Potential energy (PE) is energy that is "stored" because of the position and/or arrangement of the object. The classic example of potential energy is to pick up a brick. When it's on the ground, the brick had a certain amount of energy.

3 0
3 years ago
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What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight?Use 1.67×
vazorg [7]

The electric force on the proton is:

F = Eq

F = electric force, E = electric field strength, q = proton charge

The gravitational force on the proton is:

F = mg

F = gravitational force, m = proton mass, g = gravitational acceleration

Since the electric force and gravitational force balance each other out, set their magnitudes equal to each other:

Eq = mg

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q = 1.60×10⁻¹⁹C, m = 1.67×10⁻²⁷kg, g = 9.81m/s²

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5 0
3 years ago
The image produced by an object is –10.0 cm from a concave mirror that has a focal length of 5.0 cm. The distance of the object
Gennadij [26K]
Given:
Focal length: 5.0 cm
image produced: -10.0 cm

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1/do + 1/(-10) = 1/5
1/do = 1/5 + 1/10
1/do = (1/5 * 2/2) + (1/10 * 1/1)
1/do = 2/10 + 1/10
1/do = 3/10
10 = 3do
10/3 = do
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The distance of the object from the mirror, rounded to the nearest centimeter is 3 cm.
3 0
4 years ago
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Answer:

G=GM/r^2

G=(6.67×10^-11)(6.39×10^23)/(3390000+400000)^2

G=(6.67×10^-11)(6.39×10^23)/(3790000)^2

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Explanation:

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A question for the physicists out there:
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