Kepler found that the orbits of the planets were _____. circular amorphous oval elliptical
2 answers:
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Answer:
Electric field, E = 45.19 N/C
Explanation:
It is given that,
Surface charge density of first surface,
Surface charge density of second surface,
The electric field at a point between the two surfaces is given by :
E = 45.19 N/C
So, the magnitude of the electric field at a point between the two surfaces is 45.19 N/C. Hence, this is the required solution.