The Speed of a moving vehicle can be measured. The average time it will taken too cover both distance are shown below;
The average travel times traveled are :
0.25 meters = 2.23 seconds
0.50 meters = 3.13 seconds
Therefore, the Average travel time to cover 0.25 meters is:
(Trial 1 + Trial 2 + Trial 3) ÷ 3
(2.24 + 2.21 + 2.23) / 3 = 6.68 = 2.2266 = 2.23 seconds ( approximated to 2 decimal places).
Therefore, the Average travel time to cover 0.50 meters is
(Trial 1 + Trial 2 + Trial 3) ÷ 3
(3.16 + 3.08 + 3.15) / 3 = 9.39 ÷ 3 = 3.13 seconds
Conclusively, the average time taken to cover 0.25 and 0.50 meters is said to be 2.23 and 3.13 seconds for the both..
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Option C: Later in the day, less power is developed in lifting each box
Answer:
Option D. ²³⁹₉₃Np
Explanation:
Let the unknown be ʸₓA.
Thus, the equation becomes:
²³⁹₉₂U —> ⁰₋₁e + ʸₓA
Next, we shall determine the x, y and A. This can be obtained as follow:
92 = –1 + x
Collect like terms
92 + 1 = x
93 = x
x = 93
239 = 0 + y
239 = y
y = 239
ʸₓA => ²³⁹₉₃A => ²³⁹₉₃Np
Thus, the complete equation is:
²³⁹₉₂U —> ⁰₋₁e + ²³⁹₉₃Np
Equal to 50
law of reflection: angle of incidence equals angle of reflection
Answer:
80 m/s
Explanation:
Given:
a = -5 m/s²
v = 0 m/s
Δx = 640 m
Find: v₀
v² = v₀² + 2a(x − x₀)
(0 m/s)² = v₀² + 2(-5 m/s²) (640 m)
v₀ = 80 m/s